Slope of AB=(2-3)/(1+1)=-1/2; AC=(-1-3)/(-3+1)=-4/-2=2; BC=(-1-2)/(-3-1)=-3/-4=3/4.
The product of two sides that are perpendicular is -1. Slopes of AB and AC are perpendicular so angle A is a right angle. ABC is a right-angled triangle.
Answer:
the answer is 15896169
Step-by-step explanation:
(-x-1)(x-1)(x^2+6)
distribute from there i think?
math papa website can help with this... im not that good at math
These are all the possible answers i know from experience.
2x + 2y = 7
x^2 - 4y^2 = 8
2x = -2y + 7
x = -y + 7/2
(-y + 7/2)^2 - 4y^2 = 8
y^2 - 7y + 49/4 - 4y^2 = 8
0 = 3y^2 + 7y + 8 - 49/4
0 = 12y^2 + 28y + 32 - 49
0 = 12y^2 + 28y - 17
y = (-b ± √(b^2 - 4ac))/(2a)
y = (-28 ± √(28^2 - 4(12)(-17)))/(2(12))
Dividing by 2 is like dividing by √(4):
y = (-14 ± √(7*28 + (12)(17)))/(2*6)
y = (-7 ± √(7*7 + (3)(17)))/6
y = (-7 ± 10)/6 = 1/2 or -17/6
x = -y + 7/2 = 3 or 19/3
<span>Solutions are (3,1/2) and (19/3,-17/6)</span>
The x intercept is (1/2,0)
The y intercept is (0,4)
To find the x intercept, substitute 0 for y and and solve for x. To find the y intercept, substitute 0 for x and solve for y. Or you can graph the function and find the intercepts.
