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Volgvan
3 years ago
8

If we want to describe work, we must have

Physics
2 answers:
tresset_1 [31]3 years ago
8 0

The answer is C

Hope that helps!

Good luck :)

PtichkaEL [24]3 years ago
6 0

Answer:

The correct answer is option c.

Explanation:

Work is defined as product of the force applied on object and displacement of the object.the direction of the force and displacement of the object are same in direction.It is measures is  Joules (J).

W=F\times d

Joules(J)= Newton(N) × meter(m)

W = Work done in Joules

F = force applied in Newtons.

d = displace of the object due to applied force in miters

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A baseball has a mass of 0.145 kilograms, and a bowling ball has a mass of 6.8 kilograms. What is the gravitational force betwee
larisa [96]
We can use the equation for Newton's Law of Gravitation
Fg = (Gm₁m₂)/r²
Where gravitational constant = G = 6.674 x 10⁻¹¹ N · m²/kg²
mass m₁ = 0.145 kg
mass m₂ = 6.8 kg
distance between centers of masses = r = 0.5 m

Substitute these values into... 
Fg = (Gm₁m₂)/r²
Fg = ((6.674 x 10⁻¹¹)(0.145)(6.8)) / (0.5)²
Fg = 2.63 x 10⁻¹⁰ N 

Therefore, your answer should be 
<span>2.6 × 10–10</span>
8 0
3 years ago
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What is 8200 N/m2 expressed in kilopascals?
natima [27]
The S.I. unit for the measure of the pressure is the Pascal (Pa). 1 Pascal corresponds to
1 Pa = 1 N/m^2

We can convert the number given by the problem into Pascal:
8200 N/m^2 = 8200 Pa

And since 1 Pa = 10^{-3}kPa, we have
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5 0
3 years ago
As a skydiver accelerates downward, what force increases? A. Gravity B. Thrust C. Air resistance D. Centripetal
dybincka [34]

Answer:

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7 0
3 years ago
A rubber ball is dropped from a height of 8m. After strikingthe floor, the ball bounces to a height of 5m. a. If the ball had bo
kifflom [539]

Answer:

a) This means the collision between the ball and the floor is elastic.

b) This points to a perfectly inelastic collision between the ball and the floor as they stick together after collision

c) Check Explanation.

Explanation:

Collision of bodies are analysed according to whether both momentum and kinetic energy of the system is conserved, that is, if these two quantities before collision are equal to their values after collision.

In all types of collisions, momentum is usually conserved, but kinetic energy is conserved only in an elastic collision.

A ball dropped from a height of 8 m bounces up back to a height of 5 m.

a. If the ball had bounced to a height of 8m, how would you describe the collision between the ball and the floor?

The ball not bouncing back to a height of 8 m shows energy loss at some point in the total motion of the ball (most likely at the collision). If kinetic energy was conserved, the ball would bounce back up to the height at which it fell from (8 m) after the collision with the floor.

b. If the ball had not bounced at all, how would you describe the collision between the ball and the floor?

If the ball had not bounced at all, this means it lost all of its kinetic energy to the floor, and this points to a perfectly inelastic collision between the ball and the floor as they stick together after collision.

c. What happened to the energy lost by the ball during thecollision?

The energy lost during the collision is converted to another form, most likely responsible for some deformation on the ball & a minute deformation on the floor, converted to some form of heat as a result of the collision or into sound energy, usually, it's a combination of all This!

Hope this Helps!!!

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Where is visible light located on the electromagnetic spectrum?
nikklg [1K]
2 near the middle
between ultraviolet and infared
4 0
3 years ago
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