Answer:
Explanation:
We shall represent each displacement by vectors . i will represent east , -i west , j north and - j south .
Rhino walks 1.5 km west on day 1.
D₁ = - 1.5 i
The rhino then moves 0.7 km on a straight line in a direction of 15o east of north toward ground camera B
D₂ = .7 sin15 i + .7cos15 j
On the second day, the rhino moves 2.5 km directly south
D₃ = - 2.5 j
D = D₁ + D₂ + D₃
= - 1.5 i + .7 sin15 i + .7cos15 j - 2.5 j
= - 1.5 i + .181 i + .676 j - 2.5 j
= - 1.32 i - 1.824 j
magnitude of total displacement
= √ (1.32² +1.824²
= 2.25 km
For direction we shall calculate slope with x axis
Tanθ = - 1.824 / - 1.32
= 54°
So rhino will be towards 54° south of west as both x and y coordinates are negative.
Answer:
it is a sad day for rain to fall. Ill answer your question later
Explanation:
Answer:
The volume is decreasing at 160 cm³/min
Explanation:
Given;
Boyle's law, PV = C
where;
P is pressure of the gas
V is volume of the gas
C is constant
Differentiate this equation using product rule:
Given;
(increasing pressure rate of the gas) = 40 kPa/min
V (volume of the gas) = 600 cm³
P (pressure of the gas) = 150 kPa
Substitute in these values in the differential equation above and calculate the rate at which the volume is decreasing ( 
);
(600 x 40) + (150 x ) = 0
Therefore, the volume is decreasing at 160 cm³/min
Answer:
(b) The electrons, because they have the smaller momentum and, hence, the larger de Broglie wavelength
Explanation:
de Broglie wavelength λ = h / m v
Since both electrons and protons have same velocity , momentum mv will be less for electrons because mass of electron is less .
for electron , momentum is less so . Therefore de Broglie wavelength λ will be more for electrons .
Amount of diffraction that is angle of diffraction is proportional to λ
Therefore electrons having greater de Broglie wavelength will show greater diffraction.
The answer is as voltage increases current increases and therefore resistance would remain constant
