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Serggg [28]
2 years ago
11

What is the density of iron if 5.0 cm^3 has a mass of 39.5 g

Physics
2 answers:
shepuryov [24]2 years ago
8 0

Answer:

density =<u>mass</u><u> </u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>volume</u><u> </u>

<u>x</u><u> </u><u> </u><u> </u><u> </u><u> </u>= 39.5 ÷ 5.0

x =7.9

lana66690 [7]2 years ago
7 0

Answer:

7.9 g/cm3

Explanation:

Density = mass / volume

Density = 39.5 / 5.0

Density = 7.9 g/cm^3

Therefore, density is 7.9 g/cm^{3}<u />

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Varvara68 [4.7K]

Answer:

300,000,000 and the second question is the same.

Explanation:

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3 years ago
Hi I need help with this question (see image ). ​
Lapatulllka [165]

Explanation:

a) <em>Fixed points</em> are the temperatures at which a thermometer is calibrated. They can refer either to the actual temperatures used for calibration, or the thermometer readings at those temperatures.

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8 0
3 years ago
135g of an unknown substance gains 9133 J of heat as it is heated from 25⁰C to 100⁰C. Using the chart below, determine the ident
telo118 [61]

Answer:

The unknown substance is Aluminum.

Explanation:

We'll begin by calculating the change in the temperature of substance. This can be obtained as follow:

Initial temperature (T₁) = 25 ⁰C

Final temperature (T₂) = 100 ⁰C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 100 – 25

ΔT = 75 ⁰C

Finally, we shall determine the specific heat capacity of the substance. This can be obtained as follow:

Change in temperature (ΔT) = 75 ⁰C

Mass of the substance (M) = 135 g

Heat (Q) gained = 9133 J

Specific heat capacity (C) of substance =?

Q = MCΔT

9133 = 135 × C × 75

9133 = 10125 × C

Divide both side by 10125

C = 9133 / 10125

C = 0.902 J/gºC

Thus, the specific heat capacity of substance is 0.902 J/gºC

Comparing the specific heat capacity (i.e 0.902 J/gºC) of substance to those given in the table above, we can see clearly that the unknown substance is aluminum.

7 0
2 years ago
A room has a heater on one side and
Serjik [45]

Answer:

the warm air would be up and cool would be down

Explanation:

warm air is less dense and cool air is more dense

5 0
2 years ago
A bionic man running at 6.5 m/sec , east is acceleration at a uniform rate of 1.5 m/sec^2 east over a displacement of 100.0 m ea
tangare [24]
Given:
u = 6.5 m/s, initial velocity 
a = 1.5 m/s², acceleration
s = 100.0 m, displacement

Let v =  the velocity attained after the 100 m displacement.
Use the formula
v² = u² + 2as
v² = (6.5 m/s)² + 2*(1.5 m/s²)*(100 m) = 342.25 (m/s)²
v = 18.5 m/s

Answer: 18.5 m/s
5 0
3 years ago
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