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Serggg [28]
3 years ago
11

What is the density of iron if 5.0 cm^3 has a mass of 39.5 g

Physics
2 answers:
shepuryov [24]3 years ago
8 0

Answer:

density =<u>mass</u><u> </u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>volume</u><u> </u>

<u>x</u><u> </u><u> </u><u> </u><u> </u><u> </u>= 39.5 ÷ 5.0

x =7.9

lana66690 [7]3 years ago
7 0

Answer:

7.9 g/cm3

Explanation:

Density = mass / volume

Density = 39.5 / 5.0

Density = 7.9 g/cm^3

Therefore, density is 7.9 g/cm^{3}<u />

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While standing at the edge of the roof of a building, you throw a stone upward with an initial speed of 5.65 m/s. The stone subs
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1. 20.54m/s

2. 1.52s

Explanation:

QUESTION 1:

The speed the stone impact the ground is the final speed/velocity, which can be calculated using the formula:

v² = u² + 2as

Where;

v = final velocity (m/s)

u = initial velocity (m/s)

a = acceleration due to gravity (m/s²)

s = distance (m)

From the provided information, u = 5.65m/s, v = ?, s = 19.9m, a = 9.8m/s²

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v = 20.5417

v = 20.54m/s

QUESTION 2:

Using v = u + at

Where v = final velocity (m/s) = 20.54m/s

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