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lozanna [386]
3 years ago
10

During an autopsy and subsequent toxicology reports, it is discovered that a man died from arsenic poisoning. When investigating

the crime scene, a bottle of Gatorade was discovered next to the dead body. What type of lab technique will need to be performed first to see if there is any arsenic mixed in with the Gatorade?
Physics
1 answer:
Vaselesa [24]3 years ago
4 0

Spectrophotometry is a laboratory technique that can be performed first to check if there is presence of arsenic mixed in with Gatorade. In spectrophotometry, arsenic concentration will be measure in a specific solution by calculating the amount of light absorbed by inorganic arsenic.

Various analytical reagents are used such as molybdate reagent and variamine blue as a chromogenic reagent where a violet colored indicates presence of arsenic. 

Furthermore, new analytical reagents has been development and proposed like vanillin-2- amino nicotinic acid (VANA) and 2, 4-Dihydroxy benzophenone-2-amino thiophenol (BPBT). These are used for direct non-extractive spectrophotometric determination of arsenic. The reagent reacts with arsenic in acidic medium to form light greenish yellow colored.

 

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8 0
4 years ago
Ideal gases are often studied at standard ambient temperature and pressure (satp). The international union of pure and applied c
11Alexandr11 [23.1K]

This problem provides information about the pressure and temperature ideal gases are studied at. The answer to the questions are that all molecules have the same density, 2.43x10²⁵ mol/m³ and 2.43x10¹⁹ mol/cm³.

<h3>Idela gases</h3>

In science, we can start studying gases with the concept of ideal gas, as they do not collide one to another and are assumed to be perfect spheres with no relevant interactions.

In such a way, one can conclude that the <u>number density of all ideal gasses at SATP is the same</u>, as they are assumed to be perfect spheres with equal volumes per molecule.

Moreover, when calculating the number of molecules per cubic meter, one must use the ideal gas equation as:

PV=nRT\\\\\frac{N}{V}= \frac{P*N_A}{RT}

And plug in the numbers we are given:

\frac{N}{V}= \frac{100kPa*\frac{1000Pa}{1kPa}*6.022x10^{23}molec/mol}{8.314\frac{Pa*m^3}{mol*K}*298K}=2.43x10^{25}molec/m^3

Lastly, we can calculate the molecules per cubic centimeter by performing the following conversion:

2.43x10^{25}\frac{molec}{m^3}*(\frac{1m}{100cm} )^3\\ \\=2.43x10^{19}\frac{molec}{cm^3}

Learn more about ideal gases: brainly.com/question/26450101

5 0
3 years ago
¿Qué resistencia debe ser conectada en paralelo con una de 20 Ω para hacer una
ValentinkaMS [17]

Answer:

60 Ω

Explanation:

R(com) = 15 Ω

1/R(com) = 1/R1 + 1/R2 + 1/R3 ..... + 1/Rn

1/15 = 1/20 + 1/R2

1/R2 = 1/15 - 1/20

1/R2 = (4 - 3) / 60

1/R2 = 1/60

R2 = 60 Ω

así, la combinada de resistencia necesaria es 60 Ω

5 0
3 years ago
The record height of a man to date is 8 feet 11 inches​ (107 inches). If all men had identical body​ types, their weights would
Alisiya [41]

Answer:

679.08 lbs

Explanation:

Here it is given that

m\propto h^3

m_1 = Mass of first person = 175 pounds

h_1 = Height of first person = 70 inches

m_2 = Mass of second person

h_2 = Height of second person = 110 inches

\frac{m_1}{m_2}=\frac{h_1^3}{h_2^3}\\\Rightarrow m_2=\frac{m_1h_2^3}{h_1^3}\\\Rightarrow m_2=\frac{175\times 110^3}{70^3}\\\Rightarrow m_2=679.08\ lb

The weight of the second person would be 679.08 lbs

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