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lozanna [386]
3 years ago
10

During an autopsy and subsequent toxicology reports, it is discovered that a man died from arsenic poisoning. When investigating

the crime scene, a bottle of Gatorade was discovered next to the dead body. What type of lab technique will need to be performed first to see if there is any arsenic mixed in with the Gatorade?
Physics
1 answer:
Vaselesa [24]3 years ago
4 0

Spectrophotometry is a laboratory technique that can be performed first to check if there is presence of arsenic mixed in with Gatorade. In spectrophotometry, arsenic concentration will be measure in a specific solution by calculating the amount of light absorbed by inorganic arsenic.

Various analytical reagents are used such as molybdate reagent and variamine blue as a chromogenic reagent where a violet colored indicates presence of arsenic. 

Furthermore, new analytical reagents has been development and proposed like vanillin-2- amino nicotinic acid (VANA) and 2, 4-Dihydroxy benzophenone-2-amino thiophenol (BPBT). These are used for direct non-extractive spectrophotometric determination of arsenic. The reagent reacts with arsenic in acidic medium to form light greenish yellow colored.

 

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Answer:

The angular separation between the refracted red and refracted blue beams while they are in the glass is 42.555 - 42.283 = 0.272 degrees.

Explanation:

Given that,

The respective indices of refraction for the blue light and the red light are 1.4636 and 1.4561.

A ray of light consisting of blue light (wavelength 480 nm) and red light (wavelength 670 nm) is incident on a thick piece of glass at 80 degrees.

We need to find the angular separation between the refracted red and refracted blue beams while they are in the glass.

Using Snell's law for red light as :

n_1\sin\theta_1=n_2\sin\theta_2\\\\\theta_2=\sin^{-1}((\dfrac{n_2}{n_1})\sin\theta_1)\\\\\theta_2=\sin^{-1}((\dfrac{1}{1.4561})\sin(80))\\\\\theta_2=42.555

Again using Snell's law for blue light as :

n_1\sin\theta_1=n_2\sin\theta'_2\\\\\theta'_2=\sin^{-1}((\dfrac{n_2}{n_1})\sin\theta_1)\\\\\theta'_2=\sin^{-1}((\dfrac{1}{1.4636 })\sin(80))\\\\\theta'_2=42.283

The angular separation between the refracted red and refracted blue beams while they are in the glass is 42.555 - 42.283 = 0.272 degrees.

7 0
3 years ago
Standing still, Bruce, the quarterback, gets tackled by Biff, the 90.0-kg tackle, who is traveling at 7.0 m/s. Upon collision, B
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\\ \sf\longmapsto \Delta P=P

\\ \sf\longmapsto m1v1=m2v2

\\ \sf\longmapsto 90(7)=m2(10)

\\ \sf\longmapsto 10m2=630

\\ \sf\longmapsto m2=\dfrac{630}{10}

\\ \sf\longmapsto m2=63kg

Bruces mass is 63kg

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