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bogdanovich [222]
3 years ago
12

The heights of 10000 women students at Eastern College are known to be normally distributed, with a mean of 67 inches and a stan

dard deviation of 3 inches. How many women would you expect to be shorter than 5 ft 1 inch?
Mathematics
1 answer:
Lunna [17]3 years ago
3 0
First, convert 5ft 1inch in inches, you will get 61inches, so the probability that you need to find is P(x≤5)
Find z score: Z=(61-67)/3 = -2, with this find the probability from the z table and you get 0.0228= 2.28%, for the answer multiply 10000 by the probability 0.0228*10000= 228 women expected to be shorter that 5ft 1inch (61inches)
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nikdorinn [45]

Answer:

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Step-by-step explanation:

Solve the following system:

{4 x - y = -12 | (equation 1)

-x - y = 3 | (equation 2)

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{4 x - y = -12 | (equation 1)

0 x - (5 y)/4 = 0 | (equation 2)

Multiply equation 2 by 4/5:

{4 x - y = -12 | (equation 1)

0 x - y = 0 | (equation 2)

Multiply equation 2 by -1:

{4 x - y = -12 | (equation 1)

0 x+y = 0 | (equation 2)

Add equation 2 to equation 1:

{4 x+0 y = -12 | (equation 1)

0 x+y = 0 | (equation 2)

Divide equation 1 by 4:

{x+0 y = -3 | (equation 1)

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Collect results:

Answer: {x = -3 , y = 0

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svetlana [45]

Answer:

D)The experimental probability is greater than the theoretical probability

Step-by-step explanation:

Given:

75 times a die is rolled out of 39 times it got 6

To Find :

Which statement is true?

Solution:

The theoretical probability is given by the ,

Pt=No.of favorable outcomes/Total outcomes

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so how many times we can get 6 =1 time

Total outcomes =6

Pt=1/6

Pt=0.1667

Now for

The experimental Probability ,

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Here 39 times we get 6 and total no trails are 75

Pe=39/75

Pe=0.52

Hence we can say that Pe>Pt.

8 0
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