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4 years ago

I know this is a lot, so whoever can answer gets 50 points! PLZ HELPP!

Biology

2 answers:

liberstina [14]4 years ago

7 0

Matching

1. Metaphase

2. Cytokinesis

3. Telophase

4. Interphase

5. Anaphase

6. Prophase

7. Meiosis

8. Gene

9. I'm sorry I don't understand this question.

10. Tissue

11. Cell specialisation

12. 46, 23

13. ATP, idk the other blank sorry

14. A

15. The main function of the Krebs Cycle is to produce electron carriers that can be used in the last step of cellular respiration.

16. The light-independent reactions, or dark reactions, of photosynthesis are chemical reactions that convert carbon dioxide and other compounds into glucose. These reactions occur in the stroma, the fluid-filled area of a chloroplast outside the thylakoid membranes.

Light-dependent reactions, which take place in the thylakoid membrane, use light energy to make ATP and NADPH.

17. Aerobic respiration takes place in the presence of oxygen, produces a large amount of energy. Carbon dioxide and water are produced as the waste products. Anaerobic respiration takes place without the use of oxygen, produces small amounts of energy.

Read more on Brainly.com - brainly.com/question/11599332#readmore

Lina20 [59]4 years ago

3 0

Matching

1. Metaphase

2. Cytokinesis

3. Telophase

4. Interphase

5. Anaphase

6. Prophase

7. Meiosis

8. Gene

9. I'm sorry I don't understand this question.

10. Tissue

11. Cell specialisation

12. 46, 23

13. ATP, idk the other blank sorry

14. A

15. The main function of the Krebs Cycle is to produce electron carriers that can be used in the last step of cellular respiration.

Light-dependent reactions, which take place in the thylakoid membrane, use light energy to make ATP and NADPH.

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The magnitude of the force exerted by the elbow $f_e_l_b_o_w$ is 194.37N

Explanation:

Firstly , lets calculate the magnitude of force exerted by biceps $f_b_i_c_e_p_s$ -

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$F_b_i_c_e_p_s\times d_b_i_c_e_p_s= w_f\times\frac{d_b_a_l_l}{2} + w_b_a_l_l\times d_b_a_l_l$

(here , distance of the bicep is 2.50cm = 0.025m and distance of the ball is 36cm= 0.36m)

Now putting the given values in the formula -

$F_b_i_c_e_p_s\times 0.025= 0.95\times9.8\times\frac{0.36}{2} +1.50\times 0.36$

$F_b_i_c_e_p_s=218.38N$

Now, lets calculate the force exerted by elbow $F_e_l_b_o_w$ -

Balancing the vertical forces

$F_b_i_c_e_p_s=F_e_l_b_o_w+w_f+w_b_a_l_l$

$F_e_l_b_o_w = 218.38-(1.00\times9.8)-(0.95\times9.8)$

$F_e_l_b_o_w=194.37N$

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