F = ma
F/a = m
(25 N) / (5 m/s2) = m
4 kg = m
Answer:
r = 22.3 cm
Explanation:
given,
angular speed = 45 rev/s
tangential speed = 63 m/s
length of the rotating string
angular velocity =
ω = 2 π N
ω = 2 π x 45
ω = 282.74 rad/s
we know,
v = r ω
r = 22.3 cm
Answer: 244.05 J
Explanation:
To find speed at 30 m above the ground use equation:
V²=Vo²-2Gs
V0=31.4m/s
s=30m
G=9.81m/s²
-----------------------
V²=31.4²-2*9.81*30
V²=985.96+588.6
V²=1574.56
V=39.68m/s ---speed of arrow on 30 m obove the ground
Use equation for kinetic enrgy:
Ke=mV²/2
m=0.155kg
V=39.68m/s
-------------------------
Ke=0.155kg*(39.68m/s)²/2
Ke=0.155*1574.5/2
Ke=244.05J
Answer:
OWOWOWOOWOWOWEO. PORK = PORK NOW GIOVE BRAINLIEST BC I SAID PORK = PORK
Explanation:
