Help plz im lost
1 answer:
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Answer:
The force felt by charge 3 is F=(-5.6*10⁻⁶,3.36⁻⁵)N
Explanation:
As the superposition principle applies to static charges, we can find the net electric force as the sum of the two forces felt by q3.
Looking at the drawing and knowing that they form an equilateral triangle of lenght 4 we can conclude that each internal angle is 60°.
So, the positions in our coordinate system are:
Now using Coulomb's force:
Where d=4, q1 = -7.8*10⁻⁹C, q2 = -15.6 *10⁻⁹C, q3 = 8.0 *10⁻⁹C, k=8.98*10⁹, e0=8.8*10¹⁰:
Replacing we get 2 equations:
To work with the sam
F=∑F_i=3.5*10⁻⁴(0.023,0.032)+7*10⁻⁴(-0.016,0.032)=
=((3.5*10⁻⁴-7*10⁻⁴)*0.016,(3.5*10⁻⁴+7*10⁻⁴)*0.032)=
F=(-5.6*10⁻⁶,3.36⁻⁵)N
