1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
devlian [24]
3 years ago
5

A golf ball is released from rest from the top of a very tall building. Choose a coordinate system whose origin is at the starti

ng point of the ball, and whose y axis points vertically upward. Neglecting air resistance, calculate the ve- locity of the ball after 3.04 s. The acceleration of gravity is 9.8 m/s2 . Answer in units of m/s.
Physics
2 answers:
Alinara [238K]3 years ago
7 0

Answer: v=29.792m.s^{-1}

Explanation:

<u>Here given that:</u>

  • initial velocity of the golf ball, u =0m.s^{-1}
  • a coordinate system pointing upwards with origin at the point of release.
  • time, t = 3.04 seconds
  • acceleration due to gravity, g = 9.8 m.s^{-2}

Now, we need to find the velocity (v) after the time 3.04 s.

From the given and required data we choose the suitable equation of motion: v = u+at

Putting the given values in the above equation:

v= 0 - gt ∵the given frame of reference points in the upward directoin so we have negative on the downward side.

v=0-9.8\times 3.04

v=29.792m.s^{-1}

Zigmanuir [339]3 years ago
5 0

Answer:

Velocity of the ball after 3.04 (s) = 29.79 (m/s)

Explanation:

From the free fall movement we have the following formulas: Vf^{2} = Vo^{2} - 2gh and h=Vo*t - \frac{g*t^{2} }{2}, First we need to find the height to time iqual to 3.04 s using the formula: h=Vo*t - \frac{g*t^{2} }{2} and remember that golf ball was released from the rest (Vo= 0 (m/s)) so h= (0 (m/s))*(3.04 (s)) - \frac{9.8 (m/s^2)*(3.04 (s))^{2} }{2}, we get: h = -45.28 (m) with the height that we have got, now the velocity of the ball is calculate using Vf^{2} = Vo^{2} - 2gh solving for Vf, we get: Vf = \sqrt{Vo^{2}-2*g*h } replacing the values given Vf = \sqrt{(0 m/s)^{2}-2*(9.8 m/s^2)*(-45.28 m) }, so we get: Vf = 29.79 (m/s).

You might be interested in
A rigid tank whose volume is unknown is divided into two parts by a partition. One side of the tank contains an ideal gas at 935
a_sh-v [17]

Answer:

2805 °C

Explanation:

If the gas in the tank behaves as ideal gas at the start and end of the process. We can use the following equation:

P=RTn/V

The key issue is identify the quantities (P,T, V, n) in the initial and final state, particularly the quantities that change.

In the initial situation the gas have an initial volume V_{i}, temperature T_{i}, and pressure P,.

And in the final situation the gas have different volume V_{f} and temeperature T_{f}, the same pressure P,, and the same number of moles n,.

We can write the gas ideal equation for each state:

P=RT_{i}n/V_{i} and P=RT_{f}n/V_{f}, as the pressure are equals in both states we can write

RT_{i}n/V_{i} = RT_{f}n/V_{f}

solving for T_{f}

T_{f} = T_{i}/V_{i} * V_{f} (*)

We know T_{i}  = 935 °C, and that the V_{f} (the complete volume of the tank) is the initial volume V_{i} plus the part initially without gas which has a volume twice the size of the initial volume (read in the statement: the other side has a volume twice the size of the part containing the gas). So the final volume  V_{f}= V_{i} + 2V_{i}=3V_{i}

Replacing in (*)

T_{f} = 935/V_{i} * 3V_{i} = 935*3= 2805

7 0
3 years ago
¿Cuál es la frecuencia de rotación en la tierra?
lina2011 [118]

Answer:

frequency is approximately 11.5 µHz, or more exactly, 11.5740740e-6 Hz

Explanation:

5 0
3 years ago
Read 2 more answers
Dwarf galaxies are generally only about one-fifth the size of the andromeda galaxy. true or false
Keith_Richards [23]
It is FALSE.........
5 0
3 years ago
Read 2 more answers
Which of the following statements correctly compares the speed of waves?
ValentinkaMS [17]

Answer:

u need to put ur statements up for an answer

5 0
3 years ago
Two skydivers are holding on to each other while falling straight down at a common terminal speed of 52.30 m/s. Suddenly, they p
zalisa [80]

Answer:

v_{2,x} = - 6.259\ m/s

v_{2,y} = - 6.005\ m/s

Solution:

As per the question:

Common terminal speed, v_{cT} = 52.30\ m/s

Mass of the one of the skydiver, m_{1} = 89.30 kg

Velocity of the skydiver :

v_{1,x} = 4.430\ m/s

v_{1,y} = 4.250\ m/s

v_{1,z} = 52.30\ m/s

Mass of the other skydiver, m_{2} = 63.20 kg

Now,

To calculate the components of velocity along X and Y axes:

Before getting separated, the momentum along X-axis is zero.

After the separation, the momentum along X-axis is zero.

Therefore,

m_{1}v_{1,x} + m_{2}v_{2,x} = 0

89.30\times 4.430 + 63.20\times v_{2,x} = 0

v_{2,x} = - 6.259\ m/s

Now, consider the momentum along Y-axis:

Before separation, momentum = 0

After separation, momentum along Y-axis = 0

Therefore,

m_{1}v_{1,y} + m_{2}v_{2,y} = 0

89.30\times 4.250 + 63.20\times v_{2,y} = 0

v_{2,y} = - 6.005\ m/s

Thus the magnitude of the X and Y component of velocity are 6.259 m/s and 6.05 m/s respectively.

6 0
3 years ago
Other questions:
  • When introduced into a region where an electric field is present, an electron with initial velocity will eventually move?
    6·1 answer
  • If the magnitude of F1 is greater than the magnitude of F2, then the box is
    9·2 answers
  • A chemist identifies compounds by identifying bright lines in their spectra. She does so by heating the compounds until they glo
    7·1 answer
  • An electron is accelrated by a unifor electric field (1000v/m) pointing vertically upward. Use energy methods to get the magnitu
    7·1 answer
  • Which following is step two of the five step worksheet creation process
    6·1 answer
  • A 2200 kilogram car is accelerating at 3.4 m/s/s. what is the NET force?
    6·1 answer
  • The lamp has a resistance of 10 ohms each resistor has a resistance of 10 ohms what is the total resistance of the circuit
    12·1 answer
  • PLS HELP QUICK!!!!!!!!
    6·2 answers
  • I have a pen<br> I have a apple<br> what do I have now?
    8·2 answers
  • Which equation could not be used to determine straight line acceration?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!