A golf ball is released from rest from the top of a very tall building. Choose a coordinate system whose origin is at the starti
ng point of the ball, and whose y axis points vertically upward. Neglecting air resistance, calculate the ve- locity of the ball after 3.04 s. The acceleration of gravity is 9.8 m/s2 . Answer in units of m/s.
From the free fall movement we have the following formulas: and , First we need to find the height to time iqual to 3.04 s using the formula: and remember that golf ball was released from the rest (Vo= 0 (m/s)) so , we get: h = -45.28 (m) with the height that we have got, now the velocity of the ball is calculate using solving for Vf, we get: replacing the values given , so we get: Vf = 29.79 (m/s).
The acceleration would be 6m/sThis is because of the formula, "f/m=a" to find the acceleration; We would need to subtract the force of the friction which equals 1380, then divide that by the mass (which was 230) to get the answer 6