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Keith_Richards [23]
3 years ago
13

Abigail wants to get better at baseball. In order to do this, she has created a list of skills she will need to improve. Which s

kill should get the most of her attention in order for her to excel at baseball?
Physics
2 answers:
Tamiku [17]3 years ago
6 0

Answer:

The answer would be Power

Explanation:

When you hit a baseball with a bat. You need to have alot of power to hit that ball out of the park.

anygoal [31]3 years ago
5 0

Power is your answer :)

Have a great day!!!

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A 10-kg package drops from chute into a 25-kg cart with a velocity of 3 m/s. The cart is initially at rest and can roll freely w
amid [387]

Answer:

(a) the final velocity of the cart is 0.857 m/s

(b) the impulse experienced by the package is 21.43 kg.m/s

(c) the fraction of the initial energy lost is 0.71

Explanation:

Given;

mass of the package, m₁ = 10 kg

mass of the cart, m₂ = 25 kg

initial velocity of the package, u₁ = 3 m/s

initial velocity of the cart, u₂ = 0

let the final velocity of the cart = v

(a) Apply the principle of conservation of linear momentum to determine common final velocity for ineleastic collision;

m₁u₁  + m₂u₂ = v(m₁  +  m₂)

10 x 3   + 25 x 0   = v(10  +  25)

30  = 35v

v = 30 / 35

v = 0.857 m/s

(b) the impulse experienced by the package;

The impulse = change in momentum of the package

J = ΔP = m₁v - m₁u₁

J = m₁(v - u₁)

J = 10(0.857 - 3)

J = -21.43 kg.m/s

the magnitude of the impulse experienced by the package = 21.43 kg.m/s

(c)

the initial kinetic energy of the package is calculated as;

K.E_i = \frac{1}{2} mu_1^2\\\\K.E_i = \frac{1}{2} \times 10 \times (3)^2\\\\K.E_i = 45 \ J\\\\

the final kinetic energy of the package;

K.E_f = \frac{1}{2} (m_1 + m_2)v^2\\\\K.E_f = \frac{1}{2} \times (10 + 25) \times 0.857^2\\\\K.E_f = 12.85 \ J

the fraction of the initial energy lost;

= \frac{\Delta K.E}{K.E_i} = \frac{45 -12.85}{45} = 0.71

7 0
3 years ago
1/A ball is dropped from the top of a building. After 3 seconds, its speed is measured to be 29.4 m/s. Calculate the acceleratio
AleksAgata [21]

Answer:

9.8

Explanation:

7 0
2 years ago
A space shuttle with a mass of approximately 7.08 E5 kg is sitting on the launch pad. What would be the weight of the space shut
Afina-wow [57]

The weight of the shuttle is 6.94\cdot 10^6 N

Explanation:

The weight of an object on Earth is the gravitational force exerted by the Earth on the object.

The magnitude of the weight of an object is given by:

W=mg

where

m is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity on Earth's surface

And the direction is downward (towards the Earth's centre).

For the shuttle in this problem, its mass is

m=7.08\cdot 10^5 kg

So, its weight is

W=(7.08\cdot 10^5)(9.8)=6.94\cdot 10^6 N

Note that while the mass of an object (m) does not change, its weight (W) changes according to the location, since the value of g can be different at different location (for example, on the Moon, the value of g is about 1/6 the value of g on the Earth).

Learn more about weight and forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

6 0
3 years ago
Basketball thrown over the shoulder to make a basket: Is this a projectile? why or why not
Korvikt [17]

Answer:

An object that is thrown, kicked or otherwise launched through the air is called a projectile.

Explanation:

5 0
2 years ago
A uniform 6.84 m long horizontal beam that weighs 316 N is attached to a wall by a pin connection that allows the beam to rotate
denpristay [2]

Explanation:

Let us assume that moment about the pin and then setting it equal to zero as the rod is in equilibrium is as follows.

          Moment = Force × Leverage

        -F_{T} Sin 55^{o} \times 6.84 m + 316 N \times \frac{6.84}{2} m + 608 N \times 6.84 m

        -F_{T} \times 0.81915 \times 6.84 m + 316 N \times \frac{6.84}{2} m + 608 N \times 6.84 m = 0

                  F_{T} = 935.11 N

Therefore, we can conclude that the force (F_{T}) in the cable by assuming that the origin of our coordinate system is at the rod’s center of mass is 935.11 N.

5 0
3 years ago
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