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3 years ago

Leslie has a watering can that holds 3 liters of water. She uses 250 milliliters of water on each of her plants.

1 answer:

7 0

To find out how many plants Leslie can water you will convert the 3 Liters to milliliters and then break into groups of 250 milliliters.

3 L x 1000 mL = 3000 mL

3000 mL/250 mL = 12 plants

Leslie can water 12 plants with no remaining water.

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Irian bought 2 songbooks and a new guitar. Each songbook cost the same price. The guitar cost $250.10. Before tax, she spent a t

egoroff_w [7]

<h3>1 SongBook costs =$25.85</h3><h3>A guitar costs =$250.10, so 2 Songbooks would cost 2*25.85=51.7.</h3><h3>(2 Songbook) $51.7 * (Guitar) $250.10 = $301.80</h3>

6 0

3 years ago

Which of the following is a correct name for a side of the given angle?

Zigmanuir [339]

Answer:

C. ED

Step-by-step explanation:

The center of the angle is the point E, so it would be written first.

5 0

2 years ago

How many learners can enrol if there are 12 teachers and a ratio of teachers to learners is 30:1

VladimirAG [237]

Answer:

360 learners

Step-by-step explanation:

One way to solve these types of problems is that you could set up a proportion

learners/teachers = learners/teachers

Let x = no. of learners to enrol

30/1 = x/12

12(30) = x

x = 360 learners

5 0

3 years ago

Help!

nignag [31]

1) 8 + 4 = -5 + 7

12 = 2

FALSE

2) y = -11x + 4

(0, -7): -7 = -11(0) + 4 ⇒ -7 = 0 + 4 ⇒ -7 = 4 False

(-1, -7): -7 = -11(-1) + 4 ⇒ -7 = 11 + 4 ⇒ -7 = 15 False

(1, -7): -7 = -11(1) + 4 ⇒ -7 = -11 + 4 ⇒ -7 = -7 True

(2, 26): 26 = -11(2) + 4 ⇒ 26 = -22 + 4 ⇒ 26 = -18 False

Answer: C

3) Input Output

0 0

<u> 1 </u> 3

2 <u> 6 </u>

3 9

5 15

6 <u> 18 </u>

Rule: input is being added by 1, output is 3 times x

4) c = 65h

5) 2x = -6

$\frac{2x}{2} = \frac{-6}{2}$

x = -3

6) 8j - 5 + j = 67

9j - 5 = 67 <em>added like terms (8j + j)</em>

9j = 72

$\frac{9j}{9} = \frac{72}{9}$

j = 8

7) y = mx + b

y - b = mx

$\frac{y - b}{x} = \frac{mx}{x}$

$\frac{y - b}{x} = m$

5 0

4 years ago

Please help me I’m desperate

Dafna1 [17]

Answer:

<h2> The first</h2>

Step-by-step explanation:

$\frac29x+3>4\frac59\\{}\quad-3\quad-3\\\\\frac29x\ >\ 1\frac59\\\div\frac29\quad \, \div\frac29\\\\x>1\frac59\div\frac29\\\\x>\frac{14}9\times\frac92\\\\x>\frac{7}1\times\frac11\\\\x>7$

That means every x wich is greater than 7

4 0

3 years ago