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Nesterboy [21]
3 years ago
13

Jet aircraft maintenance crews are required to wear protective earplugs. Members of a particular crew wear earplugs that reduce

the sound intensity by a factor of 215. If, when the jet is fired up, the sound intensity level experienced by the crew members wearing protective earplugs is 87 dB, determine the sound intensity level they would experience without the earplugs.
Physics
1 answer:
Taya2010 [7]3 years ago
7 0

Answer:

So the sound intensity level they would experience without the earplugs is 110.32dB.

Explanation:

Given data

Sound intensity by factor =215

Sound intensity level =87 dB

To find

Sound intensity level they would experience without the earplugs

Solution

First we need to find the new sound intensity level

So

I_{n}=215(10^{\frac{87}{10} } )\\I_{n}=1.08*10^{11})

The dB can be calculated as:

dB=10log(I_{n})\\

Substitute the given values

dB=10log(1.08*10^{11})\\dB=110.32dB

So the sound intensity level they would experience without the earplugs is 110.32dB.

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Answer:

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Explanation:

From the question we are told that

     The weight of the horizontal solid disk is  W = 805 \  N

      The radius of the horizontal solid disk is  r =  1.58 \  m

      The force applied by the child is  F  =  49.5 \  N

       The time considered is  t =  2.95 \  s

Generally the mass of the  horizontal solid disk is mathematically represented as

          m_h  =  \frac{W}{ g}

=>       m_h  =  \frac{805}{ 9.8 }

=>       m_h  =  82.14 \  N

Generally the moment of inertia  of the horizontal solid disk is mathematically represented as  

         I  =  \frac{1}{2} *  m *  r^ 2

=>      I  =  \frac{1}{2} *  82.14 *   1.58^ 2  

=>      I  =  102.5 \  kg \cdot m^2

Generally the net torque experienced by the horizontal solid disk is mathematically represented as

           T =  I  *  \alpha   =  F *  r

=>         \alpha  =  \frac{ F  *  r }{ I }

=>         \alpha  =  \frac{  49.5  *   1.58 }{  102.53 }

=>         \alpha  = 0.7628

Gnerally from kinematic equation we have that

         w =  w_o  +  \alpha t

Here  w_o is the initial angular velocity velocity of the horizontal solid disk  which is  w_o  =  0\   rad/s

So

           w =   0  +  0.7628 * 2.95

=>        w =  2.2503 \  rad/s

Generally the kinetic energy is mathematically represented as

        KE =  \frac{1}{2}  *  I  *  w^2

=>      KE =  \frac{1}{2}  * 102.53  *  2.2503 ^2

=>      KE = 259.6 \  J

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Since the water is in circular motion, the net force must be equal to the centripetal force, so:

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Learn more about circular motion:

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