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Maru [420]
3 years ago
6

What are 3 criteria for acceleration?

Physics
1 answer:
Temka [501]3 years ago
3 0

I don't think you mean 'criteria'.  I think you mean three occurrences or
observations that indicate the presence of acceleration.

They are:

-- an object is speeding up
-- an object is slowing down
-- the direction of an object's motion is changing .

Any one of these changes is acceleration.

There's a single term that covers them all.  It is "change in velocity".


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Please help! Thanks so much! :)
notsponge [240]

Answer: B

Explanation: I'm not 100% sure tho sorry if i'm wrong

7 0
3 years ago
Water is returned from earth’s surface to the atmosphere by
Tems11 [23]

Answer:

Evaporation

Explanation:

Evaporation is a form of mass tranfer phenomena where by water are moved from the earth surface into the atmosphere as vapours,it is path of the water cycle a decription of the path moved by land water until it turns into rain, humidity,air and temperature are factors that influence evaporation though evaporation can happen at all temperature

4 0
3 years ago
The fastest pitched baseball was clocked at 46 m/s. assume that the pitcher exerted his force (assumed to be horizontal and cons
Zielflug [23.3K]
Using the Equation:
                                 v² = vi² + 2 · a · s    → Eq.1
where,
v = final velocity 
vi = initial velocity 
a = acceleration 
s = distance 

<span><span>We know that vi = 0 because the ball was at rest initially.
</span><span>
Therefore,

Solving Eq.1 for acceleration,
 
</span></span> v² = vi² + 2 · a · s
 v² = 0 + 2 · a · s
 v² = 2 · a · s
Rearranging for a,
a = v ²/2·<span>s
Substituting the values,
a = 46</span>²/2×1<span> 
a = 1058 m/s</span>² 

<span>Now applying Newton's 2nd law of motion,
 </span>
<span>F = ma
   = 0.145</span>×<span>1058

F = 153.4 N</span>
8 0
3 years ago
If a baseball pitch leaves the pitcher's hand horizontally at a velocity of 150 km/h by what percent will the pull of gravity ch
Slav-nsk [51]
<span>0.52% First, let's convert that speed into m/s. 150 km/h * 1000 m/km / 3600 s/h = 41.667 m/s Now let's see how much time gravity has to work on the ball. Divide the distance by the speed. 18 m / 41.667 m/s = 0.431996544 s Now multiply that time by the gravitational acceleration to see what the vertical component to the ball's speed that gravity adds. 0.431996544 s * 9.8 m/s^2 = 4.233566131 m/s Use the pythagorean theorem to get the new velocity of the ball. sqrt(41.667^2 + 4.234^2) = 41.882 m/s Finally, let's see what the difference is (41.882 - 41.667)/41.667 = 0.005159959 = 0.5159959% Rounding to 2 figures, gives 0.52%</span>
8 0
3 years ago
Behavior that is harmful to one's self is? 10 pts
Sophie [7]
The answer is distressing
8 0
4 years ago
Read 2 more answers
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