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musickatia [10]
3 years ago
8

Please answer this question ASAP

Mathematics
1 answer:
Radda [10]3 years ago
3 0
Your answer is highlighted! 
~Good Luck~

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Which expression is equivalent to 3+2? 
vichka [17]

Answer:

Any expression that equals 5.

Step-by-step explanation:

3 + 2 = 5, so any expression that equals 5 is equivalent to 3+2.

8 0
3 years ago
Solve only questions 1,3,5,6
Anestetic [448]

Answer:

wheres the question?

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
What is the range of the relation[(-5,0),(-4,-3),(-3,4),(-1,0),(-4,-1)]
vesna_86 [32]

The range is the set of values that the relation takes for the domain for which it is defined.

Is the set of values of the dependent variable.

In this case, we have the relation [(-5,0),(-4,-3),(-3,4),(-1,0),(-4,-1)]​.

The dependant variable takes the values: 0, -3, 4, 0 and -1. Some values are repeated.

We put the repeated values only once and sort to write the range.

Then, the range is R = {-3, -1, 0, 4}.

Answer: Range = {-3, -1, 0, 4}

4 0
1 year ago
A sum of money was to be shared among three friends,Albert,Micheal,Moses in the ratio 3:5:6.if Micheal receives $45,find the sum
kirza4 [7]

Answer:

The sum of the money shared is $1372

Step-by-step explanation:

The given ratio is

Albert:Michael:Moses=3:5:6

The total ratio is 3+5+6=14

Let the sum of money shared be $x.

Then Albert's share = 3/14 x x = 3x/ 14

Michal's Share   = 5x/14

If Michael received $196 more than Albert, then the difference between their share is the $196.

7 0
3 years ago
Area=<br> Help me please!! Thanks :)
Savatey [412]

Answer:

80π

Step-by-step explanation:

Circle O with radius IO:

large radius = IO = 12 = R

Circle O with diameter JK

IJ = JK = KL = 2 × IO = 24

IJ = JK = KL = 24/3 = 8

small radius = 8/2 = 4 = r

The shaded area is a semicircle of radius 12 minus a semicircle of radius 4 plus two semicircles of radius 4.

That is the same as

1 semicircle of radius 12 plus 1 semicircle of radius 4

A = πR²/2 + πr²/2

A = π(12² + 4²)/2

A = 160π/2

A = 80π

8 0
2 years ago
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