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3 years ago

What is 23 squared A. 1,058 B.129 C. 46 D. 529

Mathematics

2 answers:

Maslowich3 years ago

6 0

It is D. 529 because 23 squared=23×23=529

irga5000 [103]3 years ago

3 0

23 squared is 529 because 23 x 23 is 529, so the answer is D.

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The top of a ladder slides down a vertical wall at a rate of 0.675 m/s . At the moment when the bottom of the ladder is 3 m from

Svetllana [295]

Answer:

L = 5 m

Step-by-step explanation:

The ladder, the vertical wall and the ground form a right triangle. We call A and B the ends points of the ladder ( at the wall, and the ground)

If we call L the lenght of the leadder, we get

L² = y² + x²

Taking derivatives on both sides of the equation

0 = 2y Dy/dt + 2x Dx/dt

We know that Dy/dt = - 0,675 m/s (is sliding down , is decreasing)

And when x = 3 m Dx/dt = 0,9 m/s

So we can get y

0 = 2y*( -0,675) + 2*3*0,9

1,35y = 5,4

y = 5.4 /1,35 ⇒ y = 4

And L² = y² + x² ⇒ L = √ (4)² + (3)² ⇒ L √16 + 9

L = 5 m

4 0

3 years ago

Draw the triangle with vertices a(1, 1), b(5, 3), c(1, 7). find the parametrization, including endpoints, and sketch to check. (

Firlakuza [10]

Part A:

The parametric equations $x=x_1+(x_2-x_1)t$ and $y=y_1+(y_2-y_1)t$ where $0\leq t\leq1$ describes the line segment that joins the points $(x_1,\ y_1)$ and $(x_2,\ y_2)$ .

The parameterization of the line joining points A(1, 1) and B(5, 3) are given by substituting $x_1=1,\ \ y_1=1,\ \ x_2=5,\ \ y_2=3$ .

Thus, we have

x = 1 + (5 - 1)t = 1 + 4t
y = 1 + (3 - 1)t = 1 + 2t

Therefore, the parameterization of line joining points A(1, 1) and B(5, 3) are x = 1 + 4t and y = 1 + 2t.

Part B:

The parametric equations $x=x_1+(x_2-x_1)t$ and $y=y_1+(y_2-y_1)t$ where $0\leq t\leq1$ describes the line segment that joins the points $(x_1,\ y_1)$ and $(x_2,\ y_2)$ .

The parameterization of the line joining points B(5, 3) and C(1, 7) are given by substituting $x_1=5,\ \ 
y_1=3,\ \ x_2=1,\ \ y_2=7$ .

Thus, we have

x = 5 + (1 - 5)t = 5 - 4t
y = 3 + (7 - 3)t = 3 + 4t

Therefore, the parameterization of line joining points B(5, 3) and C(1, 7) are x = 5 - 4t and y = 3 + 4t.

Part C:

The parametric equations $x=x_1+(x_2-x_1)t$ and $y=y_1+(y_2-y_1)t$ where $0\leq t\leq1$ describes the line segment that joins the points $(x_1,\ y_1)$ and $(x_2,\ y_2)$ .

The parameterization of the line joining points C(1, 7) and A(1, 1) are given by substituting $x_1=1,\ \ 
y_1=7,\ \ x_2=1,\ \ y_2=1$ .

Thus, we have

x = 1 + (1 - 1)t = 1
y = 7 + (1 - 7)t = 7 - 6t

Therefore, the parameterization of line joining points A(1, 1) and B(5, 3) are x = 1 and y = 7 - 6t.

8 0

3 years ago

7 + 9 x ( 6 - 2 ) 1. 29 2.43 3. 64 4. 94 please help

timofeeve [1]

Answer:

3. 64

Step-by-step explanation:

7 + 9 x (6 - 2)

16 x 4

Hope it helps

8 0

3 years ago

Read 2 more answers

A bucket is sold at a profit equal to one - fifth of its cost price find profit percentage

Tresset [83]

Answer:

20% profit margin!

Step-by-step explanation:

Let suppose If the cost of a bucket is $100.

As the bucket is sold to 1/5 of the bucket cost.

i.e. 1/5 × 100 = $20

We know that 20% of 100 is 20.

i.e. 20/100 × 100 = 20

It mathematically means if the cost of the bucket was 100, and he sold at a profit equal to one - fifth of its cost price. It indicates that he earned a $20 profit. In other words, the person got a 20% profit percentage.

Note: I tried to take sample costs like $100 to make you understand as simple as I can.

Thus, if a bucket is sold at a profit equal to one - fifth of its cost price, the profit margin will always 20%, because if there are 5 parts of an object, 1 part makes the 20%.

I hope you get my point.

7 0

3 years ago

out of 35 librarians surveyed 12 librarians chose fantasy as their favorite 9 chose nonfiction and 14 chose fiction qhat percent

Setler [38]

14/35 = 0.4
0.4 X 100= 40%

7 0

3 years ago