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3 years ago

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Mathematics

1 answer:

scZoUnD [109]3 years ago

5 0

Step-by-step explanation:

m=y2-y1/x2-x1

m=0-(-2)/4-2

m=2/2

m=1

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Pedro le dice a María si cambias los billetes de 10 € que tienes por billetes de 5 € y los billetes de 5 € por billetes de 10 €

Bad White [126]

Answer: Maria has 10 bills of 5€ and 10 bills of 10€.

She has a total of 150€.

Step-by-step explanation:

Let be "f" the number of 5€ bills that Maria has and "t" the number of 10€ bills that Maria has.

Set up a system of equations:

$\left \{ {{f+t=20} \atop {5f+10t=10f+5t}} \right.$

Use the Substitution method to solve the system of equations:

1. Solve for "f" from the first equation:

$f=20-t$

2. Substitute the equation obtained into the second equation and solve for "t".

Then:

$5(20-t)+10t=10(20-t)+5t\\\\100-5t+10t=200-10t+5t\\\\20t-10t=100\\\\t=\frac{100}{10}\\\\t=10$

3. Substitute the value of "t" into the equation $f=20-t$ and evaluate:

$f=20-10\\\\f=10$

Therefore, Maria has 10 bills of 5€ and 10 bills of 10 €.

So the total amount of money she has, is:

$Total=10(5)+10(10)=150$

She has a total of 150€.

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3 years ago

Find the solution set of the system of linear equations represented by the augmented matrix. (if there is no solution, enter no

PIT_PIT [208]

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3 years ago

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Oduvanchick [21]

Answer:

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Step-by-step explanation:

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3 years ago

A student bought a juice drink for $2 and a sandwich the total was &6.50 how much was the sandwich

mel-nik [20]

Answer:

Step-by-step explanation:

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3 years ago

Two cards are drawn without replacement from a standard deck of 52 playing cards. What is the probability of choosing a king and

STALIN [3.7K]

Answer:

0.0181 probability of choosing a king and then, without replacement, a face card.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability of choosing a king:

There are four kings on a standard deck of 52 cards, so:

$P(A) = \frac{4}{52} = \frac{1}{13}$

Probability of choosing a face card, considering the previous card was a king.

12 face cards out of 51. So

$P(B|A) = \frac{12}{51}$

What is the probability of choosing a king and then, without replacement, a face card?

$P(A \cap B) = P(A)P(B|A) = \frac{1}{13} \times \frac{12}{51} = \frac{1*12}{13*51} = 0.0181$

0.0181 probability of choosing a king and then, without replacement, a face card.

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3 years ago