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AlladinOne [14]
3 years ago
6

What do all prokaryotes and eukaryotes have in common? A. They are unicellular organisms. B. They are multicellular organisms. C

. The cells that make them up each contain genetic information. D. The cells that make them up each contain a membrane-enclosed nucleus.
Chemistry
1 answer:
Sauron [17]3 years ago
5 0
They are multicellular
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In the Haber process for ammonia synthesis, K " 0.036 for N 2 (g) ! 3 H 2 (g) ∆ 2 NH 3 (g) at 500. K. If a 2.0-L reactor is char
lisabon 2012 [21]

Answer : The partial pressure of N_2,H_2\text{ and }NH_3 at equilibrium are, 1.133, 2.009, 0.574 bar respectively. The total pressure at equilibrium is, 3.716 bar

Solution :  Given,

Initial pressure of N_2 = 1.42 bar

Initial pressure of H_2 = 2.87 bar

K_p = 0.036

The given equilibrium reaction is,

                              N_2(g)+H_2(g)\rightleftharpoons 2NH_3(g)

Initially                   1.42      2.87             0

At equilibrium    (1.42-x)  (2.87-3x)     2x

The expression of K_p will be,

K_p=\frac{(p_{NH_3})^2}{(p_{N_2})(p_{H_2})^3}

Now put all the values of partial pressure, we get

0.036=\frac{(2x)^2}{(1.42-x)\times (2.87-3x)^3}

By solving the term x, we get

x=0.287\text{ and }3.889

From the values of 'x' we conclude that, x = 3.889 can not more than initial partial pressures. So, the value of 'x' which is equal to 3.889 is not consider.

Thus, the partial pressure of NH_3 at equilibrium = 2x = 2 × 0.287 = 0.574 bar

The partial pressure of N_2 at equilibrium = (1.42-x) = (1.42-0.287) = 1.133 bar

The partial pressure of H_2 at equilibrium = (2.87-3x) = [2.87-3(0.287)] = 2.009 bar

The total pressure at equilibrium = Partial pressure of N_2 + Partial pressure of H_2 + Partial pressure of NH_3

The total pressure at equilibrium = 1.133 + 2.009 + 0.574 = 3.716 bar

6 0
3 years ago
Which step will decrease the pressure of a gas inside a closed cubical container? increasing the number of moles of gas decreasi
Jobisdone [24]

Answer: Decreasing the temperature inside the container will decrease the pressure of a gas inside a closed cubical container.

Explanation:

According to Gay-Lussac's Law : 'The pressure of the gas increases with increase in temperature of the gas when volume of the gas is kept constant'.

(Pressure)\propto (Temperature)

At constant volume, pressure of the gas will decrease on decreasing the temperature or vice versa.

Decreasing the temperature inside the container will decrease the pressure of a gas inside a closed cubical container.

8 0
3 years ago
Read 2 more answers
In the sodium-potassium pump, sodium ion release causes two K ions to be released into the cell. __________________ True False
Solnce55 [7]

Answer:

false

Explanation:

As we know that in sodium-potassium pump .          

sodium potassium move 3Na+ outside the cells          

and  moving 2k+ inside the cells                        

so that we can say that given statement is false    

Answer FALSE                                                      

6 0
2 years ago
Which term best describes the type of bonding in magnesium chloride
max2010maxim [7]
Ionic would be the answer
5 0
2 years ago
If 65.5 moles of an ideal gas is at 9.15 atm at 50.30 °C, what is the volume of the gas?
qwelly [4]
To calculate for the volume, we need a relation to relate the number of moles (n), pressure (P), and temperature (T) with volume (V). For simplification, we assume the gas is an ideal gas. So, we use PV=nRT.

PV = nRT  where R is the universal gas constant
V = nRT / P
V = 65.5 ( 0.08205 ) (273.15 + 50.30) / 9.15 
V = 189.98 L
7 0
3 years ago
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