Aurous is a cation of gold. Gold takes the name "aurum" (Au) with atomic number of 79. In its purest form, the element is bright, slightly yellow, soft, ductile, and malleable. The charge of aurous is +1. Sulfide, on the other hand, has a charge of -2.
Hence, the chemical formula of the compound is Au₂S and its systematic name is gold (I) sulfide.
The amount of precipitate produced will be proportional to the amount of NH₃ reacted with water to produce NH₄OH.
<h3>What is precipitate?</h3>
Precipitates are the crystal type formation, when the solute is no more dissolving in the solvent.
Imagine mixing 1 tablespoon of Epsom salt with 2 cups of ammonia, the reaction is
2NH₃ + MgSO₄ + 2H₂O → Mg(OH)₂ + (NH₄)₂SO₄
The amount of precipitate produced will be proportional to the amount of NH₃ reacted with water to produce NH₄OH.
Learn more about precipitate.
brainly.com/question/18109776
#SPJ1
Answer:
Lake Ontario and St Lawrence Seaway
Explanation:
The Great Lakes are connected to the Atlantic Ocean through the St. Lawrence Seaway.
0.447 is the mole fraction of Nitrogen in this mixture.
mole fraction of nitrogen= moles of nitrogen/total moles
mole fraction of nitrogen=0.85/1.90
mole fraction of nitrogen=0.447
The product of the moles of a component and the total moles of the solution yields a mole fraction, which is a unit of concentration measurement. Because it is a ratio, mole fraction is a unitless statement. The sum of the components of the mole fraction of a solution is one. In a mixture of 1 mol benzene, 2 mol carbon tetrachloride, and 7 mol acetone, the mole fraction of the acetone is 0.7. This is computed by dividing the sum of the moles of acetone in the solution by the total number of moles of the solution's constituents:
To know more about mole fraction visit : brainly.com/question/8076655
#SPJ4
Answer:
The answer is
<h2>
</h2>
Explanation:
The pH of a solution can be found by using the formula
where
is the hydrogen ion concentration of the solution
From the question
pH = 8.25
The hydrogen ion concentration of the solution is
<u>Find antilog of both sides</u>
That's
We have the final answer as
Hope this helps you
