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Lady bird [3.3K]
3 years ago
11

The binding energy of electrons in a metal is 193 kJ/mol. Determine the threshold frequency for this metal.

Chemistry
1 answer:
Lapatulllka [165]3 years ago
4 0

Answer:

need points

Explanation:

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Consider the reaction and its equilibrium constant at 25.0 ∘C :
olga55 [171]

Since Qp>Kp , the reaction is not at equilibrium.

<h3>What is the equilibrium constant?</h3>

The equilibrium constant shows the extent to which reactants are converted into products.

Now we have to obtain the Qp as follows;

Qp =[CH3OH]/[CO] [H2]^2

Qp = 0.265/(0.265) (0.265)^2

Qp = 14.2

Now we know that Kp = 6.09×10−3, Since Qp>Kp , the reaction is not at equilibrium.

Learn more about equilibrium constant:brainly.com/question/10038290

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5 0
1 year ago
The film used to take pictures is coated with?
Naddika [18.5K]

The film which you called it is photographic film and it is strip like sheet and it's surface is clrear and transparent plastic which is coated on

two sided one side is with gelatin emulsion consists microscopic small light-sensor which is actually very sensitive in nature silver halides crystals. The size shape and other characters of the crystals gives the sensitivity,contrast of different colors combination ,and resolution of the films.

6 0
3 years ago
This diagram is attempting to compare the sizes of the four inner planets. What is wrong with this diagram?
Simora [160]

Answer:

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Explanation:

6 0
3 years ago
Read 2 more answers
Calculate the density of a material that has a mass of 50.5g and a volume of 14.5cm3.
White raven [17]
Density = mass / volume = 50.5/14.5 = 3.48 g/cm ^{3}.
4 0
3 years ago
How many moles are in 2.5L of 1.75 M Na2CO3
mixas84 [53]

Answer: There are 4.375 moles in 2.5 L of 1.75 M Na_2CO_3

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}      

Molarity of solution = 1.75 M

Volume of solution = 2.5 L  

Putting values in equation , we get:

1.75M=\frac{\text{Moles of} Na_2CO_3}{2.5L}\\\\\text{Moles of }Na_2CO_3=1.75mol/L\times 2.5L=4.375mol

6 0
2 years ago
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