<h3>
Answer: False</h3>
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Explanation:
I'm assuming you meant to type out
(y-2)^2 = y^2-6y+4
This equation is not true for all real numbers because the left hand side expands out like so
(y-2)^2
(y-2)(y-2)
x(y-2) .... let x = y-2
xy-2x
y(x)-2(x)
y(y-2)-2(y-2) ... replace x with y-2
y^2-2y-2y+4
y^2-4y+4
So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4
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Another approach is to pick some y value such as y = 2 to find that
(y-2)^2 = y^2-6y+4
(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2
0^2 = 2^2 - 6(2) + 4
0 = 4 - 6(2) + 4
0 = 4 - 12 + 4
0 = -4
We get a false statement. This is one counterexample showing the given equation is not true for all values of y.
Answer:
Step-by-step explanation:
False you must multiply the coefficient (numbers) and add the exponents.
Answer:
To find a complex conjugate, simply change the sign of the imaginary part (the part with the i). This means that it either goes from positive to negative or from negative to positive.
As a general rule, the complex conjugate of <span>a+bi</span> is <span>a−bi</span>.
Therefore, the complex conjugate of <span>3−2i</span> is <span>3+2i</span>.
Hope this helped!!... :D
Please correct me if I'm wrong!!.. :3
Answer:
x = 6
Step-by-step explanation:
Love proportions!
3x+2(x+6) = 35(21)
21(3x+2) = 35(x+6)
63x + 42 = 35x + 210
28x = 168
x = 6
