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Neko [114]
3 years ago
13

If a straight-chain hydrocarbon is a gas at room temperature, how many carbon atoms will it have?

Chemistry
1 answer:
Orlov [11]3 years ago
6 0

The fewer the carbon atoms, the closer it is  to being a gas. The only one you have to check out is A which is hexane. You know that gasoline at the pumps has 8 carbons and its a liquid. So B and C are both not gases  because they are above 8.

C6 (hexane) is a liquid at room temperature not a gas.

The answer is D. If there is a gas present, it must be C3

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Please help me!!!!!!​
Leona [35]

The answer is B

To write the equilibrium constant for an equation, all you have to do is divide the products by the reactants. The reactants are always on the left side, and the products are always on the right side. The coefficients of the elements will be written as the exponent of that same element. However, in this equation, we do not have to write any exponents, as there are no coefficient but 1.

5 0
3 years ago
How many significant numbers are there in 40.00
muminat

The answer to this is 4.

3 0
3 years ago
Read 2 more answers
HELP O DONT UNDERSTAND THIS!IM SOOO STRESSED HOW DO I SOLVE IT
katrin [286]

Answer:

.86

.48

Explanation:

19/25 x 4/4 = 86/100

86/100 = .86

12/25 x 4/4 = 48/100

48/100 = .48

4 0
3 years ago
100 points!! Brainliest if correct!!
snow_tiger [21]
Answer A: CO2

Reason: carbon dioxides formula is CO and the number next to it is the molecules
6 0
3 years ago
Read 2 more answers
A meteorologist filled a weather balloon with 3.00L of the inert noble gas helium. The balloon's pressure was 765 torr. The ball
yanalaym [24]

Answer:

4.33 L

Explanation:

Step 1: Given data

Initial volume of the balloon (V₁): 3.00 L

Initial pressure of the balloon (P₁): 765 torr

Final  volume of the balloon (V₂): ?

Final pressure of the balloon (P₂): 530 torr

Step 2: Calculate the final volume of the balloon

If we consider Helium to behave as an ideal gas, we can calculate the final volume of the balloon using Boyle's law.

P_1 \times V_1 =  P_2 \times V_2\\V_2 = \frac{P_1 \times V_1}{P_2} = \frac{765torr \times 3.00L}{530torr} = 4.33 L

7 0
3 years ago
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