Question

How many milliliters of this solution are required to prepare 1.00 L of 0.130 M K2Cr2O7 ?

Answer 1

Answer:

First you'll need to divide the mass of K2Cr2O7 by its molar mass and volume which should be easy but I'll do some of it to help you out

Explanation:

$K_{2}Cr_{2}O_{7}$

$2K = 39.098 = 2(39.098) = 78.196$

$2Cr = 51.996 = 2(51.996) = 103.992$

and

$7O = 15.999 = 7(15.999) = 111.993$

$78.196 + 103.992 + 111.993 = 294.181$

so that's the mass of K2Cr2O7 and then you divide it by the molar mass and volume.

Hopefully you can do that on your own! Hope I helped a bit atleast and I have a good feeling about 0.438 but I don't want you to just guess