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inna [77]
2 years ago
14

How many milliliters of this solution are required to prepare 1.00 L of 0.130 M K2Cr2O7 ?

Chemistry
1 answer:
ra1l [238]2 years ago
7 0

Answer:

First you'll need to divide the mass of K2Cr2O7 by its molar mass and volume which should be easy but I'll do some of it to help you out

Explanation:

K_{2}Cr_{2}O_{7}

2K = 39.098 = 2(39.098) = 78.196

2Cr = 51.996 = 2(51.996) = 103.992

and

7O = 15.999 = 7(15.999) = 111.993

78.196 + 103.992 + 111.993 = 294.181

so that's the mass of K2Cr2O7 and then you divide it by the molar mass and volume.

Hopefully you can do that on your own! Hope I helped a bit atleast and I have a good feeling about 0.438 but I don't want you to just guess

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4.50 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 1
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Answer:

\mathbf{C_{10}H_8}   ( Naphthalene )

Explanation:

Given that:

4.50 g of a Compound X is made up of Carbon , Hydron and Oxygen

It's molecular molar mass = 128 g/mol

Compound X undergoes combustion reaction and the product yield :

CO_2 with mass 15.47g and :

H_2O with mass 2.53 g

The objective is to use this information to determine the molecular formula of X.

We all know that ; number of moles = mass/molar mass

where the molar mass of H_2O is 18 g/mol

number of moles of H_2O product = 2.53 g/18 g/mol

number of moles of H_2O product = 0.1406 moles

Also; the molar mass of CO_2 product = 44 g/mol

number of moles of CO_2 product = 15.47g/ 44 g/mol

number of moles of CO_2 product =  0.3516 moles

number of moles of Compound X in the reactant side= 4.50 g /128 g/mol

number of moles of Compound X n the reactant side= 0.03516 moles

Now; number number of moles of CO_2 in reactant = 0.3516 moles/0.03516 moles

Now; number number of moles of CO_2 in reactant = 10

number of moles of H_2O reactant = 0.1406 moles × 2/0.03516

number of moles of H_2O reactant = 7.997 ≅ 8

Since we said the Compound X is known to be made of Carbon C , Hydrogen H and Oxygen O

Then the molecular formula can be written as :

\mathbf{C_{10}H_8O_{x}}

In order to find the x; we have

128  = (12 × 10 + 1 × 8 + 16 × x)

128 = 120 + 8 + 16x)

128  =  128 + 16 x

128 - 128 = 16 x

0 = 16 x

x = 0/16

x = 0

As x = 0 ; hence there are no oxygen present in the reaction

Thus; the molecular formula of Compound X = \mathbf{C_{10}H_8} which is also known as Naphthalene

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