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Aleonysh [2.5K]
2 years ago
12

Hello everyone any one free for c h a t​

Chemistry
1 answer:
sleet_krkn [62]2 years ago
4 0

Reply:

Hi! What ch4t? i'd like to know ^^

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Just a curious question to the Chemists,
Vikki [24]

Answer:

well the world would be shocked

Explanation:

and suprise

8 0
3 years ago
Calculate the specific heat in calories per °C of a 2.00 lb pure iron bar.<br> Plz help me!!!
nekit [7.7K]

Answer:

402.7897

Explanation:

Pretty sure but not 100% about it.

grams in 2 pounds = 907.184 * specific heat of iron = .444

=402.789696

4 0
2 years ago
Which of the following statements is incorrect? Group of answer choices The product of wavelength and frequency of electromagnet
morpeh [17]

Answer: Option (b) is the correct.

Explanation:

It is known that energy is directly proportional to frequency.

Mathematically,              E \propto \nu

or,                           E = h \times \nu ............ (1)

where,     E = energy

                h = Plank's constant

              \nu = frequency

This relation shows that higher is the energy then more will be the frequency of electrmagnetic radiation.

Also,     \nu = \frac{c}{\lambda} ......... (2)

where,          c = speed of light

                 \lambda = wavelength

Therefore, substituting value of \nu from equation (2) into equation (1) as follows.

                 E = h \times \nu

                 E = h \times \frac{c}{\lambda}

This relation shows that higher is the energy then lower will be the wavelength.

Thus, we can conclude that as the energy of a photon increases, its frequency decreases, is incorrect statement.

3 0
3 years ago
The barium isotope 133ba has a half-life of 10.5 years. a sample begins with 1.1×1010 133ba atoms. how many are left after (a) 5
Sladkaya [172]
<span>a) 7.9x10^9 b) 1.5x10^9 c) 3.9x10^4 To determine what percentage of an isotope remains after a given length of time, you can use the formula p = 2^(-x) where p = percentage remaining x = number of half lives expired. The number of half lives expired is simply x = t/h where x = number of half lives expired t = time spent h = length of half life. So the overall formula becomes p = 2^(-t/h) And since we're starting with 1.1x10^10 atoms, we can simply multiply that by the percentage. So, the answers rounding to 2 significant figures are: a) 1.1x10^10 * 2^(-5/10.5) = 1.1x10^10 * 0.718873349 = 7.9x10^9 b) 1.1x10^10 * 2^(-30/10.5) = 1.1x10^10 * 0.138011189 = 1.5x10^9 c) 1.1x10^10 * 2^(-190/10.5) = 1.1x10^10 * 3.57101x10^-6 = 3.9x10^4</span>
4 0
3 years ago
Read 2 more answers
What is the type of compound of copper and oxide?
kykrilka [37]
Copper<span>(II) </span>oxide<span> or cupric </span>oxide<span> is the inorganic </span>compound<span> with the formula CuO. A black solid, it is one of the two stable </span>oxides<span> of </span>copper, the other being Cu2<span>O or cuprous </span>oxide<span>. As a mineral, it is known as tenorite and paramelaconite.</span>
5 0
3 years ago
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