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ahrayia [7]
3 years ago
5

The diameter of a red blood cell is about 3 × 10−4 in. What is its diameter in centimeters?

Chemistry
2 answers:
lesantik [10]3 years ago
8 0

Answer:

1 in. =2.54 cm

3*(10^-4)*2.54=7.62*10^-4

Explanation:

eduard3 years ago
7 0
7.62 • 10^ -4 explanation in photo

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Which statement describes an Arrhenius acid? A. It is a proton donor. B. It is a proton acceptor. C. It produces hydroxide ions
Katen [24]
Hello.

The answer is: D it produces hyrogen ions in a solution.

This is correct because when Arrhenius acid it turns into hydrogen ions.substance as an acid if it produces hydrogen ions H(+) or hydronium ions in water. A substance is classified as a base if it produces hydroxide ions OH(-) in water.

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3 0
3 years ago
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Questions and answers about isotopes grade 8 I need this for a PowerPoint exam projects
DanielleElmas [232]

Answer:

Question: A patient is diagnosed with a damage in the thyroid gland.

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3 0
2 years ago
If is found that 24.68 mL of .1165 M NaOH is needed to titrate .2931 g of an unknown acid to the phenolphthalein end point. Calc
Lemur [1.5K]

Answer: The equivalent mass of the acid is 83.16 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}  

Molarity of NaOH solution = 0.1165 M

Volume of NaOH solution = 24.68 mL = 0.02468 L

Putting values in equation 1, we get:

\text{Moles of} NaOH={0.1165M}\times{0.02468L}=2.875\times 10^{-3}moles=2.875\times 10^{-3}geq    

( as acidity of NaOH is 1)

For end point:  gram equivalents of acid =  gram equivalents of base = 2.875\times 10^{-3}

Mass of acid=gram equivalents\times {\text {Equivalent mass}}

0.2391=2.875\times 10^{-3}\times {\text {Equivalent mass}}

{\text {Equivalent mass}}=83.16g

Thus equivalent mass of the acid is 83.16 grams

5 0
3 years ago
How many grams of Cl are in 345 g of CaCl2
swat32
Hope this helps you.

3 0
3 years ago
Using the standardized NaOH solution in the previous
geniusboy [140]

Answer:

Using the standardized NaOH solution in the previous question, the titration of 5.00 mL of vinegar required 42.25 mL of NaOH. What is the % of acetic acid in the vinegar? Concentration of NaOH from previous question= 0.0986 M. David C

Explanation:

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6 0
3 years ago
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