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Vikki [24]
2 years ago
9

The magnetic field lines due to a straight, current-carrying wire are __________. The magnetic field lines due to a straight, cu

rrent-carrying wire ar
Physics
1 answer:
Rama09 [41]2 years ago
4 0

The magnetic field lines due to a straight, current-carrying wire are circular.

<u>Explanation:</u>

The concepts of Electromagnetism brought a new revolution to the science world. The idea is the source of many new modes of power and machines that reduces the manual work. Motors are the best example of machines that run on the concepts of electromagnetism. So the concept is that a current-carrying conductor induces a magnetic field in its nearby premise.

This magnetic field can perceive by the magnetic line of forces. Now, if we pour some iron dust around a current-carrying conductor, we'll see a concentric circular pattern around the straight wire whose centre will be at the conductor axis. The pattern of these magnetic lines of force may deflect with the variation of current in the wire but remain in the circular format.

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What is the value of the thickness of the boundary layer at leading edge of the plate?
Harman [31]

Along the flow direction, the boundary layer's thickness varies. For ReT values between 260 and 780, the boundary layer thickness—defined as the depth at which the normalized concentration has a value of 1/e—ranges between 800 and 250 m.

<h3>What is the Boundary layer?</h3>
  • A boundary layer is the thin layer of fluid that forms immediately around a bounded surface in physics and fluid mechanics as a result of the fluid flowing along the surface.
  • A no-slip boundary condition is created as a result of the fluid and wall interaction (zero velocity at the wall).
  • After that, the flow velocity above the surface steadily rises until it reaches the bulk flow velocity again.
  • The term "velocity boundary layer" refers to the thin layer of fluid whose velocity has not yet recovered to that of the main flow.
<h3>What purpose does a boundary layer serve?</h3>
  • Because it is on the fluid's boundary, engineers refer to this layer as the boundary layer.
  • Many aerodynamics issues, such as wing stall, skin friction drag on an object, and the heat transfer that takes place in high-speed flight, depend heavily on the specifics of the flow within the boundary layer.

Learn more about Boundary layer here:

brainly.com/question/12974964

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7 0
1 year ago
A 1.0-kg ball has a velocity of 12 m/s downward just before it strikes the ground and bounces up with a velocity of 12 m/s upwar
Nezavi [6.7K]

Answer:

The change in momentum of the ball is 24 kg-m/s  

Explanation:

It is given that,

Mass of the ball, m = 1 kg

Initial velocity of the ball, u = -12 m/s (in downwards)

Final velocity of the ball, v = +12 m/s (in upward)

We need to find the change in momentum of the ball.

Initial momentum of the ball, p_i=mu=1\ kg\times (-12\ m/s)=-12\ kg-m/s

Final momentum of the ball, p_f=mv=1\ kg\times (12\ m/s)=12\ kg-m/s

Change in momentum of the ball, \Delta p=p_f-p_i

\Delta p=12-(-12)=24\ kg-m/s

So, the change in momentum of the ball is 24 kg-m/s. Hence, this is the required solution.

3 0
3 years ago
Thunder is heard 7.2 seconds after a bolt of lightning is observed. if the speed of sound is 349 m/s, how far away did the light
Natasha2012 [34]

Answer:

2512.8 meters

Explanation:

s=d/t

by using speed formula

5 0
1 year ago
cycling at 13.0 m/s on your new aero carbon fiber bike, how much times would it take a pro cyclist to ride in 120 km? Give your
sp2606 [1]

We have that the time in seconds, minutes, and hours is

t=1.083*10^{-4}s

T_{min}=1.805*10^{-6}min

T_{hours}=3.0083*10^{-8}hours

From the Question we are told that

Velocity v=13.0m/s

Distance d=120 km

Generally the equation for the Time  is mathematically given as

t=\frac{13}{120*10^3}\\\\t=1.083*10^{-4}s

Therefore

T_{min}=1.083*10^{-4}s/60

T_{min}=1.805*10^{-6}min

And

T_{hours}=T_{min}/60

T_{hours}=3.0083*10^{-8}hours

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4 0
3 years ago
Which statement is true of equinoxes? They occur in June and December. Days and nights are equal in length everywhere. The lengt
Zanzabum
<span>Days and nights are equal in length everywhere.(gradpoint)</span>
8 0
2 years ago
Read 2 more answers
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