Answer:
Le calcul du courant se fait avec deux éléments : la tension et la valeur de la résistance. Courant (A) = tension (V) / résistance (Ohm) ce qui donne la formule I = U/R.
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Answer:
A C
Explanation:
The statement of the exercise is a bit strange, but if the distance between the load increases.
The following phenomena must occur.
* If the charge has a spatial distribution, the electric field should reduce the electric field of a point charge at the same distance
* As the distance increases the value of the electric field decreases in quadratic form
therefore when reviewing the correct answers are
if the total load is q, answer A is correct
and answer C is always correc
Answer:
λ= 5.24 × 10 ⁻² nC/cm
Explanation:
Given:
distance r = 4.10 cm = 0.041 m
Electric field intensity E = 2300 N/C
K = 9 x 10 ⁹ Nm²/C
To find λ = linear charge density = ?
Sol:
we know that E= 2Kλ / r
⇒ λ = -E r/2K (-ve sign show the direction toward the wire)
λ = (- 2300 N/C × 0.041 m) / 2 × 9 x 10 ⁹ Nm²/C
λ = 5.24 × 10 ⁻⁹ C/m
λ = 5.24 nC/m = 5.24 nC/100 cm
λ= 5.24 × 10 ⁻² nC/cm
Https://courses.physics.illinois.edu/phys102/sp2013/lectures/lecture2.pdf
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Answer:
0.99kgm/s
Explanation:
Given parameters:
Initial momentum = 5.8kgm/s
Final momentum = 6.79kgm/s
Unknown:
Magnitude of the impulse applied to the baseball = ?
Solution:
To solve this problem;
The impulse applied to the baseball can be found by using the expression below:
Impulse = Final momentum - Initial momentum
Impulse = 6.79kgm/s - 5.8kgm/s = 0.99kgm/s