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liberstina [14]
3 years ago
5

A truck weighing 5 * 10^3 kgf and a cart weighting 500 kgf are moving with the same speed compare their kinetic energies?​

Physics
1 answer:
Lisa [10]3 years ago
5 0

A truck weighing 5 x 10³ kg force.

A cart weighing 500 kg force.

Moving with the same speed complete their

kinetic energies.

As we know that,

Formula of:

→ Kinetic energy = 1/2 x m x v².

Using this formula in the equation, we get.

(1).

→ For truck = 1/2 x 5 x 10³ x v².-----

→ For cart = 1/2 x 500 x v². -----(2).

Divide equation (1) and (2), we get.

⇒ KE₁/KE₂ = 5 x 10³/5 x 10².

➡ KE₁/KE₂ = 10/1.

⇒ KE₁/KE₂ = 10:1.

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Answer:

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If we say the charge of each particle is q, then:

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3 years ago
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false

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A force is acting on the planet
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A 37 cm long solenoid, 1.8 cm in diameter, is to produce a 0.50 T magnetic field at its center. If the maximum current is 4.4 A,
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Answer:

33,458.71 turns

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Solution:

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⇒ n = B/ (μ₀ × I)

n = 0.50 T / ( 4 π × 10 ⁻⁷ × 4.4 A)

n = 90,428.94 turn/m

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8 0
3 years ago
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A 20 N south magnetic force pushes a charged particle traveling with a velocity of 4 m/s west through a 5 T magnetic field point
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Answer:

<u>Charge</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>particle</u><u> </u><u>is</u><u> </u><u>1</u><u> </u><u>coulomb</u><u>.</u>

Explanation:

Force, F:

{ \bf{F=BeV}}

F is magnetic force.

B is the magnetic flux density.

e is the charge of the particle.

V is the velocity

{ \sf{20 = (5 \times e \times 4)}} \\ { \sf{20e = 20}} \\ { \sf{e = 1 \: coulomb}}

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