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2 years ago

A truck weighing 5 * 10^3 kgf and a cart weighting 500 kgf are moving with the same speed compare their kinetic energies?

Physics

1 answer:

Lisa [10]2 years ago

5 0

A truck weighing 5 x 10³ kg force.

A cart weighing 500 kg force.

Moving with the same speed complete their

kinetic energies.

As we know that,

Formula of:

→ Kinetic energy = 1/2 x m x v².

Using this formula in the equation, we get.

(1).

→ For truck = 1/2 x 5 x 10³ x v².-----

→ For cart = 1/2 x 500 x v². -----(2).

Divide equation (1) and (2), we get.

⇒ KE₁/KE₂ = 5 x 10³/5 x 10².

➡ KE₁/KE₂ = 10/1.

⇒ KE₁/KE₂ = 10:1.

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Uma massa de 500 Kg desloca-se com velocidade 58 km por hora. Calcule o módulo de sua quantidade por movimento

Simora [160]

The momentum of the object is 8050 kg m/s

Explanation:

The momentum of an object is defined as

$p=mv$

where

p is the momentum

m is the mass

v is the velocity of the object

For the object in this problem, we have

m = 500 kg is its mass

v = 58 km/h is its velocity

Converting the velocity into m/s,

$v=58 \frac{km}{h}\cdot \frac{1000 m/km}{3600 s/h}=16.1 m/s$

Therefore now we can find the momentum of the object:

$p=(500)(16.1)=8050 kg m/s$

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7 0

3 years ago

A mass is attached to a vertical spring, which then goes into oscillation. At the high point of the oscillation, the spring is i

andrew-mc [135]

Answer:

0.34 sec

Explanation:

Low point of spring ( length of stretched spring ) = 5.8 cm

midpoint of spring = 5.8 / 2 = 2.9 cm

Determine the oscillation period

at equilibrum condition

Kx = Mg

g= 9.8 m/s^2

x = 2.9 * 10^-2 m

k / m = 9.8 / ( 2.9 * 10^-2 ) = 337.93

note : w = $\sqrt{k/m}$ = $\sqrt{337.93}$ = 18.38 rad/sec

Period of oscillation = $2\pi / w$

= 0.34 sec

8 0

3 years ago

A ladder rests against a vertical wall at a point 12 feet from the floor. The angle formed by the ladder and the floor is 63°. C

GenaCL600 [577]

Answer:

length of the ladder is 13.47 feet

base of wall to latter distance 6.10 feet

angle between ladder and the wall is 26.95°

Explanation:

given data

height h = 12 feet

angle 63°

to find out

length of the ladder ( L) and length of wall to ladder ( A) and angle between ladder and the wall

solution

we consider here angle between base of wall and floor is right angle

we apply here trigonometry rule that is

sin63 = h/L

put here value

L = 12 / sin63

L = 13.47

so length of the ladder is 13.47 feet

and

we can say

tan 63 = h / A

put here value

A = 12 / tan63

A = 6.10

so base of wall to latter distance 6.10 feet

and

we say here

tanθ = 6.10 / 12

θ = 26.95°

so angle between ladder and the wall is 26.95°

8 0

2 years ago

Which of the following is true about a planet orbiting a star in uniform circular

Mnenie [13.5K]

The velocity vector of the planet points toward the center of the circle is the following is true about a planet orbiting a star in uniform circular motion.

A. The velocity vector of the planet points toward the center of the circle.

<u>Explanation:</u>

Motion of the planet around the star is mentioned to be uniform and around a circular path. Objects in uniform circular motion motion has constant angular speed but the velocity of the object will not remain constant. Since the planet is in circular motion the direction of velocity vector at a particular point is tangential to the circular path at that particular point.

Thus at every point, the direction of velocity vector changes and this means the velocity is never constant. The objects in uniform circular motion has centripetal acceleration which means that velocity vector of the planet points toward the center of the circle.

7 0

3 years ago

Mary and her younger brother Alex decide to ride the carousel at the State Fair. Mary sits on one of the horses in the outer sec

GaryK [48]

Mary and her younger brother Alex decide to ride the carousel at the State Fair, Mary's and Alex's angular speed M and tangential speed vM is mathematically given as

Mary's and Alex's angular speed=1.43

Tangential speed mary=3.22 m/s

Tangential speed alex =2.260m/s

<h3>What is Mary's and Alex's angular speed M and tangential speed vM?</h3>

Generally, the equation for angular speed is mathematically given as

$w=2\pi /T\\\\Therefore\\\\w=2\pi/3.9$

w = 1.61 rev/see 3.9

Centripetal acc mary = v^2/r

Centripetal acc mary = w^2r

Centripetal acc mary = w^2x 2m

Centripetal acc. of Alex = w²x L.u

Therefore

$\frac{(ac) mary }{(ac) plex}= 1.43$

Hence

tang. speed V=Wr

tang. speed of mary = 1.61x2 = 3.22 m/s

tang. speed of Alex: 1.61X1·4 =2.260m/s

A truck weighing 5 * 10^3 kgf and a cart weighting 500 kgf are moving with the same speed compare their kinetic energies?​

A truck weighing 5 * 10^3 kgf and a cart weighting 500 kgf are moving with the same speed compare their kinetic energies?