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4 years ago

When large amplitude sound vibrates the ear significantly, a _______ results.

Physics

1 answer:

sladkih [1.3K]4 years ago

4 0

The answer is B. High Pitch Sound

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a block of mass m slides along a frictionless track with speed vm. It collides with a stationary block of mass M. Find an expres

shusha [124]

Answer:

Part a) When collision is perfectly inelastic

$v_m = \frac{m + M}{m} \sqrt{5Rg}$

Part b) When collision is perfectly elastic

$v_m = \frac{m + M}{2m}\sqrt{5Rg}$

Explanation:

Part a)

As we know that collision is perfectly inelastic

so here we will have

$mv_m = (m + M)v$

so we have

$v = \frac{mv_m}{m + M}$

now we know that in order to complete the circle we will have

$v = \sqrt{5Rg}$

$\frac{mv_m}{m + M} = \sqrt{5Rg}$

now we have

$v_m = \frac{m + M}{m} \sqrt{5Rg}$

Part b)

Now we know that collision is perfectly elastic

so we will have

$v = \frac{2mv_m}{m + M}$

now we have

$\sqrt{5Rg} = \frac{2mv_m}{m + M}$

$v_m = \frac{m + M}{2m}\sqrt{5Rg}$

6 0

4 years ago

What is the work done by a car's braking system when it slows the 1500-kg car from an initial speed of 96 km/h down to 56 km/h i

kondor19780726 [428]

Answer:

-352.275KJ

Explanation:

We are given that

Mass of car=1500kg

Initial speed of car =u=96 km/h= $96\times \frac{5}{18}=26.67m/s$

1km/h= $\frac{5}{18}m/s$

Final speed of car=v=56km/h= $56\times \frac{5}{18}=15.56m/s$

Distance traveled by car=s=55m

We have to find the work done by the car's braking system.

Using third equation of motion

$v^2-u^2=2as$

$(15.56)^2-(26.67)^2=2a(55)$

$-469.18=110a$

$a=\frac{-469.18}{110}=-4.27m/s^2$

Where negative sign indicates that velocity of car decreases.

Work done by a car's barking system= $w=F\times s=ma\times s$

Work done by a car's barking system= $1500\times -4.27\times 55=352275J$

Work done by a car's barking system= $-\frac{352275}{1000}=-352.275KJ$

1KJ=1000J

Where negative sign indicates that work done in opposite direction of motion.

7 0

4 years ago

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Rita places a 2.5 kg block on a frictionless inclined plane that is 30 degrees above horizontal. She applies a horizontal force,

vitfil [10]

Answer:

14.2

Explanation:

find horizontal force of the weight = 2.5kg x 9.8 Sin30 = 12.3 N

to prevent the sliding she needs to pull horizontally

Fh = 12.3 /Cos 30 =14.2N

7 0

3 years ago

WILL GIVE YOU BRAINLIST IF YOU ANSWER

kvv77 [185]

Answer:

thanks

Explanation:

willow ptarmigan

5 0

3 years ago

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A box is against a wall. A person pushes on the box, but the box does not move. Is this situation an example of a force

Leya [2.2K]

Answer: I don’t think so, because the box is ALREADY against the wall so you can’t move it further into the wall

Explanation:

7 0

3 years ago

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