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ELEN [110]
3 years ago
13

WILL GIVE YOU BRAINLIST IF YOU ANSWER

Physics
2 answers:
GalinKa [24]3 years ago
6 0

Answer:

 

Explanation:

 

kvv77 [185]3 years ago
5 0

Answer:

thanks

Explanation:

willow ptarmigan

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According to Newton's Third Law of Motion, what happens when two objects of unequal masses collide?
maksim [4K]
<span>Newton's third law is that for every action, there is an equal and opposite reaction.
A </span><span>Damage is not a part of physics, at least I don't think it is. </span><span>
B </span>Is just downright wrong. If anything, the smaller mass will be pushed forward with the heavier mass. <span>
C Sounds correct
D It'</span><span>s wrong, because the masses are not equal, or else they would stop.</span>
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It’s 11:53pm right now and I have just this assignment left to do for this class, I need this assignment done so I don’t fail th
Vlada [557]

Answer:

Explanation:

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What body parts were scientists wanting to image that prompted the development of the CT scanner
zalisa [80]

Answer:

The head

Explanation:

4 0
3 years ago
Potential energy becomes kinetic energy when:
Sedbober [7]

Answer:

An object has potential energy (stored energy) when it is not in motion. Once a force has been applied or it begins to move the potential energy changes to kinetic energy (energy of motion).

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5 0
2 years ago
Below is a circuit schematic of sources and resistors (Figure 3). VS = 10V , R1 = 100Ω, R2 = 50Ω, R3 = 25Ω, IS = 2A. Calculate t
lorasvet [3.4K]

Answer:

V_3\approx 4.28\,\,V

I_1=0.0572\,\,amps

I_3\approx 0.171\,\,amps

Explanation:

Notice that this is a circuit with resistors R1 and R2 in parallel, connected to resistor R3 in series. It is what is called a parallel-series combination.

So we first find the equivalent resistance for the two resistors in parallel:

\frac{1}{Re}= \frac{1}{R1}+\frac{1}{R2}\\\frac{1}{Re}= \frac{1}{100}+\frac{1}{50}\\\frac{1}{Re}= \frac{3}{100}\\Re=\frac{100}{3} \,\,\Omega

By knowing this, we can estimate the total current through the circuit,:

Vs=I\,*\,(\frac{100}{3} +25)\\10=I\,*\,\frac{175}{3} \\I=\frac{30}{175} \,amps

So approximately 0.17  amps

and therefore, we can estimate the voltage drop (V3) in R3 uisng Ohm's law:

V_3=\frac{30}{175} *\,25=\frac{30}{7} \approx 4.28\,\,V

So now we know that the potential drop across the parellel resistors must be:

10 V -  4.28 V = 5.72 V

and with this info, we can calculate the current through R1 using Ohm's Law:

I_1=\frac{V_1}{R_1} =\frac{5.72}{100} =0.0572\,\,amps

4 0
3 years ago
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