Part 1)
here Julie is running at speed 5 m/s
So here two balls are thrown at speed 10 m/s towards Julie with respect to her friend standing on the ground.
So here this all speed is real speed of all.
Now as per Anita (let say she is one of her friend standing on ground) the speed of two balls will be same as the given speed as she is observing from ground or stationary frame
As per the frame of Julie
speed of ball 1
towards her in same side
speed of ball 2
towards her from opposite side
Part b)
Now in this case the speed of two balls is given with respect to Julie
so we can say
for ball 1
so in ground frame speed of ball 1 is
Similarly for ball 2
So speed in ground frame of ball 2 is
so its 5 m/s from opposite side
The ball is using an reaction and opposite reaction, so when you dribble a basketball you push the ball with downward force and the ground pushes the ball back up thus making the opposite reaction.
Answer:
The intensity increased by a factor of 158489
Explanation:
Given that,
Sound level = 95.0 dB
Sound level = 43.0 dB
Frequency = 10000 Hz
We need to calculate the ratio of sound intensity
Using formula of sound level
Put the value into the formula
...(I)
.....(II)
Subtracting these equations
Taking inverse log
Hence, The intensity increased by a factor of 158489
Ohms law = v= Ir
V= 0.02 x 4000 = 80v