Answer:
4.64E14
Explanation:
First convert 645 nm to m = 6.4500E-7m. The equation for finding v with these values is the speed of light/wavelength. so 2.998E8/6.4500E-7m.
so your v or frequency would equal 4.64E14
Fun fact you know this is visible light because the visible light range is within the E14 range.
Answer is: <span>de Broglie wavelength of a proton is </span>3,4·10⁻⁵ nm.
v(proton) = 0,038 · 3·10⁸ m/s.
v(proton) = 1,14·10⁷ m/s; speed of proton.
m(proton) = 1,67·10⁻²⁷ kg.
h = 6,62607004·10⁻³⁴ m²·kg/s; Planck constant.
λ(proton) = h / m(proton) · v(proton).
λ(proton) = 6,62607004·10⁻³⁴ m²·kg/s ÷ (1,67·10⁻²⁷ kg · 1,14·10⁷ m/s).
λ(proton) = 3,48·10⁻¹⁴ m · 10⁹ nm/m = 3,4·10⁻⁵ nm.
I guess it is gases
I think , coz it has its own shape
Moves randomly
Answer:
the correct answer is Group of answer choices
