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3 years ago

Bases in solution produce what type of ions?

1 answer:

4 0

Bases produce hydroxide ions, while acids produce hydrogen ions.

Bases have a pH of above 7, and are bitter and slippery.

Answer: <span>c. hydroxide ions</span>

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assume that a water balloon has the same number of water molecules as a helium balloon has helium atoms. If the mass of the wate

Aloiza [94]

Answer : The mass of the water molecule is 4.5 times greater than the mass of the helium atom.

Explanation :

Assumption : The number of water molecules is equal to the number of helium atoms

Given : The mass of water = 4.5 × The mass of helium ........(1)

The mass of Water = Mass of 1 water molecule × Number of water molecule

The mass of Helium = Mass of 1 helium atom × Number of helium atom

Now these two masses expression put in the equation (1), we get

Mass of 1 water molecule × Number of water molecule = 4.5 × Mass of 1 helium atom × Number of helium atom

As per assumption, the number of water molecules is equal to the number of helium atoms. The relation between the mass of water molecule and the mass of helium atom is,

Mass of water molecule = 4.5 × Mass of helium atom

Therefore, the mass of the water molecule is 4.5 times greater than the mass of the helium atom.

3 0

3 years ago

What is the atomic weight of Na?

Zigmanuir [339]

Answer:

22.989769 u

Explanation:

The atomic weight of any atom can be found by multiplying the abundance of an isotope of an element by the atomic mass of the element and then adding the results together. This equation can be used with elements with two or more isotopes: Carbon-12: 0.9889 x 12.0000 = 11.8668. Carbon-13: 0.0111 x 13.0034 = 0.1443.

6 0

3 years ago

Need help !!!!! ASAP

Julli [10]

<h2>Hello!</h2>

The answer is:

The new volume will be 1 L.

$V_{2}=1L$

To solve the problem, since we are given the volume and the first and the second pressure, to calculate the new volume, we need to assume that the temperature is constant.

To solve this problem, we need to use Boyle's Law. Boyle's Law establishes when the temperature is kept constant, the pressure and the volume will be proportional.

Boyle's Law equation is:

$P_{1}V_{1}=P_{2}V_{2}$

So, we are given the information:

$V_{1}=2L\\P_{1}=50kPa\\P_{2}=100kPa$

Then, isolating the new volume and substituting into the equation, we have:

$P_{1}V_{1}=P_{2}V_{2}$

$V_{2}=\frac{P_{1}V_{1}}{P_{2}}$

$V_{2}=\frac{50kPa*2L}{100kPa}=1L$

Hence, the new volume will be 1 L.

$V_{2}=1L$

Have a nice day!

4 0

3 years ago

C2H4(g) + H2(g) → C2H6(g) ΔH = –137.5 kJ; ΔS = –120.5 J/K Calculate ΔG at 25 °C and determine whether the reaction is spontaneou

Katen [24]

Answer:-ΔG=-101.5KJ

Explanation:We have to calculate ΔG for the reaction so using the formula given in the equation we can calculate the \Delta G for the reaction.

We need to convert the unit ofΔS in terms of KJ/Kelvin as its value is given in terms of J/Kelvin

Also we need to convert the temperature in Kelvin as it is given in degree celsius.

$\Delta H=-137.5\\ \Delta S=-120J/K\\ \Delta S=-0.120KJ/K\\ T=25^{.C}\\ T=273+25=298 K\\ \Delta G=?\\ \Delta G=\Delta H-T\Delta S\\\Delta G=-137.5KJ-(278\times -0.120)\\ \Delta G=-137.5+35.76\\\Delta G=-101.74\\\Delta G=Negative$

After calculating forΔG we found that the value ofΔG is negative and its value is -101.74KJ

For a reaction to be spontaneous the value of \Delta G \ must be negative .

As the ΔG for the given reaction is is negative so the reaction will be spontaneous in nature.

In this reaction since the entropy of reaction is positive and hence when we increase the temperature term then the overall term TΔS would become more positive and hence the value of ΔG would be less negative .

Hence the value of ΔG would become more positive with the increase in temperature.

So we found the value of ΔG to be -101.74KJ

4 0

3 years ago

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ValentinkaMS [17]

Answer:

1: A

2: C

3: D

4: D

5: B

Explanation:

4 0

3 years ago

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