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emmainna [20.7K]
3 years ago
9

What are some interesting facts about Dmitri Mendeleev?

Chemistry
1 answer:
Amiraneli [1.4K]3 years ago
6 0
Dmitri Mendeleev was born in Tobolsk on the 8th of February 1834.
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Why do engineers use metals in making<br> electrical wires
Montano1993 [528]

Answer:

Why is copper used for most electrical wiring? All metals have some amount of resistivity to electrical currents, which is why they require a power source to push the current through. The lower the level of resistivity, the more electrical conductivity a metal has

4 0
3 years ago
What is true about energy in an ordinary chemical reaction? Energy is
Lisa [10]
The answer is statement #3.
4 0
3 years ago
Read 2 more answers
Na2CrO4 + PbCL2<br> Formula in double replacement
Marta_Voda [28]

Na₂CrO₄ + PbCl₂ → PbCrO₄ + 2 NaCl

<u>Explanation:</u>

In a double displacement reaction, the reactants which are involved in the reaction exchanging their ions thereby produces 2 new compounds. Here sodium chromate and lead chloride are undergoing double displacement reaction, the ions exchanges their position there by forming sodium chloride and lead chromate. So the double displacement reaction is given as,

Na₂CrO₄ + PbCl₂ → PbCrO₄ + 2 NaCl

6 0
3 years ago
Fill in the coefficients that will balance the following reaction: a0NaCl + a1FeO → a2Na2O + a3FeCl2
Helen [10]

Answer:

2NaCl + FeO —-> 2Na2O + FeCl2

Explanation:

4 0
3 years ago
Calculate the heat absorbed by the water in a calorimeter when 175 grams of lead cools from 125.0°C to 22.0°C. The specific heat
Iteru [2.4K]

Answer:

Q = 233.42 J

Explanation:

Given data:

Mass of lead = 175 g

Initial temperature = 125.0°C

Final temperature = 22.0°C

Specific heat capacity of lead = 0.01295 J/g.°C

Heat absorbed by water = ?

Solution:

Heat  absorbed by water is actually the heat lost by the metal.

Thus, we will calculate the heat lost by metal.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 22.0°C - 125.0°C

ΔT = -103°C

Q = 175 g × 0.01295 J/g.°C×-103°C

Q = -233.42 J

Heat absorbed by the water is 233.42 J.

5 0
3 years ago
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