Answer:
P₂= 116.7 atm
Explanation:
Here apply the Boyle's law equations that states :at constant temperature the volume of a dry mass of a gas is inversely proportional to its pressure.
This is simplified as;
P₁V₁=P₂V₂ where P is pressure and V is volume
Given that;
P₁=1
V₁=1.81 m³
P₂=?
V₂=1.55*10^-2 m³
Apply the formula
1*1.81 =P₂*1.55*10^-2 m³
1.81/1.55*10^-2 =P₂
P₂= 116.7 atm
Answer:
Explanation:
Initial pressure, P = 125 kPa
Initial temperature, T = 25.0°C
If new pressure is increased to P' = 150.0 kPa
We need to find new temperature. According to Gay-Lussac's law,
P ∝ T
or
So, the new temperature will be 
.
Answer:
The correct answer is - water acts as a ligand that splits d orbitals.
Explanation:
Hydrated CuSO4 has a central metal (Cu) surrounded by the water molecules, here water molecules play a role of the ligands that causes the splitting of d-orbitals. This splitting brings d-d transition and emits the blue color of Cu in the visible light.
Anhydrous CuSO4 on other hand is colorless due to the lack of molecules of ligand that makes splitting of d orbitals impossible so no transition of d-d orbitals takes place and no emission of color.
Argon is a noble gas. Argon has a full outer shell. This makes it so that it does not need to react with any of the other elements to be stable.
With Rubidium and Cobalt its a whole different story.
I hope that helps!
