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Sveta_85 [38]
3 years ago
5

Calculate the average atomic mas of an unknown element that has two naturally-occurring isotopes.

Chemistry
2 answers:
professor190 [17]3 years ago
8 0
The average atomic mass if the element above is calculated by the sum of the product of the isotope abundance and its atomic mass unit. It is expressed as:

Average atomic mass = Σ xi(Mi)
<span>Average atomic mass = (.7547 x 248.7) + (.2453 x 249.4) = 248.87
</span>
Hope this helps.
jonny [76]3 years ago
7 0

Answer:

248.9 uma

Explanation:

We calculate the average atomic mass using the following formula

m= \frac{(m_1.\%_1)+(m_2.\%_2)}{100} \\

This formula depends on how many isotopes the atom has.

If the atom had three isotopes another term would be added to the formula

m1= 248.7 uma\\\%_1= 75.47\%\\m_2= 249.4 uma\\\%_2= 24.53\%

m= \frac{(248.7)(75.47)+(249.4)(24.53)}{100}\\ m=248.9 uma

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How many moles of ammonium nitrate will be produced 110.0g of ammonium carbonate
marshall27 [118]

Answer:

                     2.288 Moles of NH₄NO₃

Explanation:

The Balance chemical equation is as follow:

                  (NH₄)₂CO₃ + 2 HNO₃  →  2 NH₄NO₃ + H₂O + CO₂

To solve this problem we will do following steps:

Finding moles of Ammonium Carbonate:

As we know,

                        Moles  =  Mass / M.Mass

So,

                        Moles  =  110 g  /  96.08 g/mol

                        Moles  =  1.144 moles

Calculating moles of Ammonium Nitrate:

According to balance chemical equation;

                      1 mole of (NH₄)₂CO₃ produces  =  2 moles of NH₄NO₃

So,

          1.144 moles of (NH₄)₂CO₃ will produce  =  X moles of NH₄NO₃

Solving for X,

                     X =  2 moles × 1.144 moles ÷ 1 mole

                     X  =  2.288 moles of NH₄NO₃

8 0
3 years ago
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