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Sveta_85 [38]
3 years ago
5

Calculate the average atomic mas of an unknown element that has two naturally-occurring isotopes.

Chemistry
2 answers:
professor190 [17]3 years ago
8 0
The average atomic mass if the element above is calculated by the sum of the product of the isotope abundance and its atomic mass unit. It is expressed as:

Average atomic mass = Σ xi(Mi)
<span>Average atomic mass = (.7547 x 248.7) + (.2453 x 249.4) = 248.87
</span>
Hope this helps.
jonny [76]3 years ago
7 0

Answer:

248.9 uma

Explanation:

We calculate the average atomic mass using the following formula

m= \frac{(m_1.\%_1)+(m_2.\%_2)}{100} \\

This formula depends on how many isotopes the atom has.

If the atom had three isotopes another term would be added to the formula

m1= 248.7 uma\\\%_1= 75.47\%\\m_2= 249.4 uma\\\%_2= 24.53\%

m= \frac{(248.7)(75.47)+(249.4)(24.53)}{100}\\ m=248.9 uma

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12.00 moles of naclo3 will produce how many grams of O2? (Moles to Grams)
Sergeu [11.5K]
2NaClO₃   →  2NaCl  +  3O₂

mole ratio of NaClO₃  to  O₂  is  2  :  3

∴  if moles of NaClO₃  =  12 mol

then moles of O₂  =  \frac{12 mol   *   3}{2}
      
                             =  18 mol


Mass of O₂  =  mol of O₂  ×  molar mass of O₂
 
                    =  18 mol  × 16 g/mol
 
                    =  288 g

So I wasn't sure which equation to use since you did not specify so I just used the decomposition reaction.  If you should have used another reaction then just follow the same steps and you'll get your answer.




4 0
3 years ago
What type of energy has caused the fewest deaths per unit of energy produced?
mash [69]

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4 0
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Which of these lab safety procedures is INCORRECT?
Ksju [112]

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6 0
3 years ago
Air is trapped in a cylinder fitted with a piston that occupies 150.5 mL at 1.12 atm pressure. What is the new volume when the p
wolverine [178]

Answer:

New volume V2 = 120.4 ml

Explanation:

Given:

Pressure P1 = 1.12 atm

New pressure P2 = 1.12[1+0.25] = 1.4 atm

Old volume V1 = 150.5 ml

Find:

New volume V2

Computation:

P1V1 = P2V2

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V2 = 120.4 ml

New volume V2 = 120.4 ml

5 0
3 years ago
You have 47.0 mL of a 2.00 M concentrated or "stock" solution that must be diluted to 0.500 M. How much water should you add?
Inessa [10]

The required volume of water to make the dilute solution of 0.5 M is 188 mL.

<h3>How do we calculate the required volume?</h3>

Required volume of water to dilute the stock solution will be calculated by using the below equation as:

M₁V₁ = M₂V₂, where

  • M₁ & V₁ are the molarity and volume of stock solution.
  • M₂ & V₂ are the molarity and volume of dilute solution.

On putting values from the question to the above equation, we get

V₂ = (2)(47) / (0.5) = 188mL

Hence required volume of water is 188 mL.

To know more about volume & concentration, visit the below link:
brainly.com/question/7208546

#SPJ1

6 0
2 years ago
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