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Aleks [24]
3 years ago
7

The result of one experiment carried out by a research team would be considered valid if

Chemistry
1 answer:
Kaylis [27]3 years ago
7 0
Where is the rest of the question.
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2 years ago
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What is the ph of a solution of 0.550 m k2hpo4, potassium hydrogen phosphate?
Solnce55 [7]
We assume that we have Ka= 4.2x10^-13 (missing in the question)
and when we have this equation:
H2PO4 (-) → H+  + HPO4-
and form the Ka equation we can get [H+]:
Ka= [H+] [HPO4-] / [H2PO4] and we have Ka= 4.2x10^-13 & [H2PO4-] = 0.55m
by substitution:
4.2x10^-13 = (z)(z)/ 0.55
z^2 = 2.31x 10^-13
z= 4.81x10^-7
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when PH equation is:

PH= -㏒[H+]
     = -㏒(4.81x10^-7) = 6.32

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