Answer:
M KIO3 = 1.254 mol/L
Explanation:
∴ w KIO3 = 553 g
∴ mm KIO3 = 214.001 g/mol
∴ volumen sln = 2.10 L
⇒ mol KIO3 = (553 g)×(mol/210.001 g) = 2.633 mol
⇒ M KIO3 = (2.633 mol KIO3 / (2.10 L sln)
⇒ M KIO3 = 1.254 mol/L
Answer:
8.3028894e-22
Explanation:
5x10^2 atoms/1 x 1 mol/6.022x10^23
Answer:
pH = 11.05
Explanation:
It is possible to answer this question using Henderson-Hasselbalch formula:
pH = pka + log₁₀ [A] / [HA⁺]
Where A in this case is weak base (dimethylamine) and conjugate acid (HA⁺) is dimethylamine hydrochloride.
As Ka= Kw / Kb = 1x10⁻¹⁴ / 7.4x10⁻⁴ = 1.35x10⁻¹¹ And pKa is -log Ka = <em>10.87 </em> pH of the solution is:
pH = 10.87 + log₁₀ [0.600] / [0.400]
<em>pH = 11.05</em>
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I hope it helps!
