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4 years ago

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A 3.10-mm-long, 430 kgkg steel beam extends horizontally from the point where it has been bolted to the framework of a new build

ing under construction. A 69.0 kgkg construction worker stands at the far end of the beam.What is the magnitude of the gravitational torque about the point where the beam is bolted into place?

1 answer:

Alex17521 [72]4 years ago

4 0

Answer:

Explanation:

Given that,

The length of the beam L = 3.10m

The mass of the steam beam $m_1$ = 430kg

The mass of worker $m_2$ = 69.0kg

The distance from the fixed point to centre of gravity of beam = $\frac{L}{2}$

and our length of beam is 3.10m

so the distance from the fixed point to centre of gravity of beam is

$\frac{3.10}{2}=1.55m$

Then the net torque is

$=-W_sL'-W_wL\\\\=-(W_sL'+W_wL)$

$W_s$ is the weight of steel rod

$=430\times9.8=4214N$

$W_w$ is the weight of the worker

$=69\times9.8\\\\=676.2N$

Torque can now be calculated

$-(4214\times1.55+676.2\times3.9)Nm\\\\-(6531.7+2637.18)Nm\\\\-(9168.88)Nm$

≅ 9169Nm

<h3>Therefore,the magnitude of the torque is 9169Nm</h3>

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Answer:

The tension in the cable is 19387.5 N.

Explanation:

Given:

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Time taken by the elevator (t) = 2.15 s

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Let the tension in the cable wire be 'T' Newtons.

Now, there are 2 forces acting in the vertical direction. One is tension in the upward direction and the other the weight of the elevator in the downward direction.

As the elevator is accelerating upward, the net force acts in the upward direction.

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Plug in the given values and solve for 'T'. This gives,

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In a Rutherford scattering experiment, an alpha particle is accelerated toward a stationary silver nucleus. If the closest appro

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Explanation:

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Let K be the initial kinetic energy of alpha particle and r be the closest approach distance. So,

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Learn more about Newton's second law of motion:

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