All categories

3 years ago

In world war 1 , Multiple reflection was used in submarines. How multiple reflection works and helps in such situation?

Physics

1 answer:

prisoha [69]3 years ago

8 0

Answer:

Submarines use a device called Periscope that uses the concept of multiple reflections and help us see objects above the water surface.

Explanation:

When a light ray falls on a reflecting surface like a mirror, it gets reflected. In multiple reflections, the incident light ray is made to reflect multiple times by arranging the reflecting surfaces in different ways.

In submarines, we use Periscope, which is a long tube like structure. The long tube is bent at ends. It uses two simple mirrors which are placed parallel to each other at an angle of 45 degrees. The light from one mirror gets reflected to the other mirror, thus causing a multiple reflection.

You might be interested in

Current is constant at all points in a parallel circuit. True False

Sergio [31]

This is false. Current is the speed of the charge, 1 amp of current is 1 coulomb per second. So you can imagine the current of a circuit as the current of a river. In a parallel circuit, the river breaks into two separate streams. Some of the water goes down one river, some goes down the other. However, the total amount of water/coulombs never changes. This means that some of the total current will go down one river, and one the other. However, with less coulombs now the current will decrease.

Long story short, since there are two paths, the charge will split and depending on the resistance of each parallel stream a different amount of charge will go down each branch.

5 0

3 years ago

A particle moves along a straight path through displacement while force acts on it. (Other forces also act on the particle.) Wha

allsm [11]

a) c = 1.85

b) c = 0.8

c) c = 2.33

Explanation:

The displacement of the particle is given by

$d=2.2i+cj$

While the force applied on the particle is

$F=3.2i-3.8 j$

So we have a problem in 2-dimensions.

The work done on the particle is given by the scalar product between force and displacement:

$W=F\cdot d$ (1)

Here the work done on the particle is zero, so

W = 0

Therefore from eq(1) we find:

$0=(3.2i-3.8j)\cdot (2.2i+cj)=7.04-3.8c\\3.8c=7.04\\c=\frac{7.04}{3.8}=1.85$

In this problem, the work done on the particle is

$W=4.0 J$

The force and displacement are still

$d=2.2i+cj$ (displacement)

$F=3.2i-3.8 j$ (force)

Therefore, by calculting the scalar product between force and displacement and equating it to the work done (4.0 J), we find:

$W=F\cdot d$

$4.0 =(3.2i-3.8j)\cdot (2.2i+cj)=7.04-3.8c\\3.8c=3.04\\c=\frac{3.04}{3.8}=0.8$

In this problem instead, the work done on the particle is negative:

$W=-1.8 J$

As before, the force and displacement are

$d=2.2i+cj$ (displacement)

$F=3.2i-3.8 j$ (force)

And so again, we calculate the scalar product between force and displacement and we equate it to the work done on the particle, -1.8 J.

Doing so, we find:

$W=F\cdot d$

$-1.8=(3.2i-3.8j)\cdot (2.2i+c)=7.04-3.8c\\3.8c=8.84\\c=\frac{8.84}{3.8}=2.33$

7 0

3 years ago

A speedboat travels from the dock to the first buoy, a distance of 20 meters, in 18 seconds. It began the trip at a speed of 0 m

LenaWriter [7]

So as a fact we do not know if the boat "burned tires" to reach the buoy :) the average velocity is +1,11 m/s. 20m divided by 18 seconds is +1.11 m/s

5 0

3 years ago

Read 2 more answers

An example of a land feature formed by river erosion is?

KatRina [158]

There are various examples of land features formed by river erosion. One of them is Delta. A delta is formed when sediments are deposited in a place where a river flow into an ocean or lake and build up a land form. Thus, a river delta is a land form that occurs as a result of deposition of sediments carried by a river as the flow leaves its mouth and enter a slow moving or stagnant water.

7 0

3 years ago

What is the wavelength of violet light that has a frequency of 7.5x10^14

Crank

Λ= V/f
but change it to represent the speed of light, c 
λ= c/f 
c = 3.00 x 10^8 m/s 
Plug in your given info and solve for λ(wavelength) 
λ= 3.00 x 10^8 m/s / 7.5 x 10^14 Hz
(3.00 x 10^8) / (7.5 x 10^14) = 300,000,000 / 750,000,000,000,000 = 0.0000004
Hope this helps :)

6 0

3 years ago

Read 2 more answers