The grid in a triode is kept negatively charged to prevent...

Physics

2 answers:

stepladder [879]3 years ago

5 0

Answer:

B. the electrons from being attracted to the grid instead of the anode.

Explanation:

just because its the answer

Anestetic [448]3 years ago

4 0

I think the correct answer is the third statement, electron from escaping from the tube containing the triode. The negative charge on the grid repels any electron in the tube. As a result,the flow of current is controlled. If the field is that strong, all current flow will stop resulting to maintaining the electron cloud in the tube.

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What minimum volume must the slab have for a 75.0 kgkg woman to be able to stand on it without getting her feet wet

Alisiya [41]

V = 0.9375 m3 is minimum volume .

<h3>What is density ?</h3>

We use the word "density" to indicate how much space (or "volume") an object or substance occupies in relation to the amount of matter contained therein (its mass).
Density can also be defined as the quantity of mass per unit of volume. A dense object is one that is both hefty and small.

Given,

1000 kg/m3 = density of water

920 kg/m3 = density of ice

BF = Woman Weight + Slab Weight

Pvg = 75 + Pvg

V = 75 kg / (1000 - 920)

V = 75 / 80

V = 0.9375 m3

Therefore, V = 0.9375 m3 is minimum volume .

Learn more about density

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6 0

2 years ago

suppose the ball has the smallest possible frequency that allows it to go all the way around the circle. what tension in the str

tatyana61 [14]

The complete question is missing, so i have attached the complete question.

Answer:

A) FBD is attached.

B) The condition that must be satisfied is for ω_min = √(g/r)

C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).

Explanation:

A) I've attached the image of the free body diagram.

B) The formula for the net force is given as;

F_net = mv²/r

We know that angular velocity;ω = v/r

Thus;

F_net = mω²r

Now, the minimum downward force is the weight and so;

mg = m(ω_min)²r

m will cancel out to give;

g = (ω_min)²r

(ω_min)² = g/r

ω_min = √(g/r)

The condition that must be satisfied is for ω_min = √(g/r)

C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).