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Karolina [17]
3 years ago
13

A 6.0-kg object moving 5.0 m/s collides with and sticks to a 2.0-kg object. after the collision the composite object is moving 2

.0 m/s in a direction opposite to the initial direction of motion of the 6.0-kg object. determine the speed of the 2.0-kg object before the collision.
Physics
1 answer:
vredina [299]3 years ago
5 0
  <span>m1v1 + m2v2 = (m1+m2)*(-vf) 
6*5 + 2*v2 = (6 + 2)*(-2) 
v2 = -16/2 = -8 m/s i</span>
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W = 1.5 x 10⁶ J = 1.5 MJ

Explanation:

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ΔV = Potential Difference = V₂ - V₁ = -8.9 V - 6.7 V = - 15.6 V

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