Question: If the subspace of all solutions of
Ax = 0
has a basis consisting of vectors and if A is a matrix, what is the rank of A.
Note: The rank of A can only be determined if the dimension of the matrix A is given, and the number of vectors is known. Here in this question, neither the dimension, nor the number of vectors is given.
Assume: The number of vectors is 3, and the dimension is 5 × 8.
Answer:
The rank of the matrix A is 5.
Step-by-step explanation:
In the standard basis of the linear transformation:
f : R^8 → R^5, x↦Ax
the matrix A is a representation.
and the dimension of kernel of A, written as dim(kerA) is 3.
By the rank-nullity theorem, rank of matrix A is equal to the subtraction of the dimension of the kernel of A from the dimension of R^8.
That is:
rank(A) = dim(R^8) - dim(kerA)
= 8 - 3
= 5
Amphitrite1040Answer:
Amphitrite1040
Step-by-step explanation:
Answer:
The degrees of freedom for this sample are 27.
The sample size to get a margin of error equal or less than 0.3656 is n=4450.
Step-by-step explanation:
The degrees of freedom for calculating the value of t are:
With 27 degrees of freedom and 95% confidence level, from a table we can get that the t-value is t=2.052.
The sample size to get a margin of error equal or less than 0.3656 can be calculated as:
Answer:
84
Step-by-step explanation:
Let the first digit = x
Let the second digit =y
x + y = 12
x + 4 = 3*y
===========
From the second equation, we learn that x = 3y - 4
Put that into the first equation.
3y - 4 + y = 12 Combine the left side
4y - 4 = 12 Add 4 to both sides
4y = 16 Divide by 4
4y/4 = 16/4
y = 4
=================
x + 4 = 12
x + 4 - 4 = 12-4
x = 8
So the number is 84
