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Sholpan [36]
3 years ago
14

Solve the following equation. –4y + 8 = 4(2y – 2) – 2(–16 + 8y) A. y = –4 B. y = 4 C. y = –2 D. y = –6 I need Help I am utterly

useless.
Mathematics
1 answer:
leonid [27]3 years ago
3 0
The answer is B. (y = 4)


Further explanation:

–4y + 8 = 4(2y – 2) – 2(–16 + 8y)
= -4y + 8 = 4 * (2y -2) - 2 * (-16 + 8y)
= -4y + 8 = ( 4 * 2y - 4 *2 ) - (2 * -16 - 2 * 8y )
= -4y + 8 = 8y - 8 - ( -32 - 16y)
= -4y + 8 = 8y - 8 + 32 + 16y
Move y’s to the left & numbers to the right
= -4y - 8y - 16y = -8 + 32 - 8
= 12y - 16y = -16 + 32
Y = 16 / 28
Y = 4 = (B choice)
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Step-by-step explanation: Ordinal variables are simply categorical in nature just like nominal variables, however, the difference exists in the fact that ordinal labels posses an ordered rank or level unlike nominal variables. Though the extent or width of the difference between these labels cannot be ascertained. In the scenario above, size of businesses are labeled qualitatively with labels such as : small, medium and large. This labels depicts and follow a certain order with small being the least, then medium, then large. Telling us large businesses are superior in size to small and medium and medium is superior to large. Though the extent of the difference cannot be accurately ascertained.

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3 years ago
Please help me with my homework<br><br> <img src="https://tex.z-dn.net/?f=%5Cbf%7B%28x%2B9%29%5E5%7D" id="TexFormula1" title="\b
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Answer:

x⁵+ 45x⁴+ 810x³+ 7290x²+ 32805x +59049

Step-by-step explanation:

Greetings !

Given expression

(x + 9) {}^{5}

write 5 as a sum

(x + 9) {}^{3 + 2}

use \: a {}^{m + n}  = a {}^{m}  \times a {}^{n} to \: expand \: the \: expression.

(x + 9) {}^{3}  \times (x + 9) {}^{2}

Use (a+b)³=a³+3a²b+b³ to expand the expression

(x {}^{3}  + 27x {}^{2}  + 243x + 729) \times (x + 9) {}^{2}

Use (a+b)²=a²+2ab+b² to the second expression to expand it

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Finally, simplify the expression gives

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2 years ago
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4) Finally, divide both sides by 4
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