All categories

3 years ago

5. Sara has a photo that is 5 inches by 7 inches. When she adds a frame

Mathematics

1 answer:

stiv31 [10]3 years ago

5 0

Answer:

1 inch

Step-by-step explanation:

Factors of 63 are 7 and 9, each of which is 2 more than the dimensions of the photo. Sarah's frame is 1 inch wide.

_____

A 1-inch wide frame adds 2 inches to length and width.

_____

Solution using an equation

If you let w represent the width of the frame, the area of the framed photo is ...

(5+2w)(7+2w) = 63

4w^2 +24w -28 = 0 . . . . write in standard form

w^2 +6w -7 = 0 . . . . . . . . divide by 4

(w -1)(w +7) = 0 . . . . . . . . factor

The positive solution to this equation is w=1.

The width of the frame is 1 inch.

You might be interested in

Find the area of the irregularly-shaped hexagon below

Ber [7]

let each box length be 1

for white triangle

area = ½bh

=½(4)(2)

for orange triangle

area=½(2)(3)

for blue marked boxes

each of the box

area=l²

=(1)²

there are 16 boxes

so the total area will be 16

total area of the hexagon = 4+3+16

=23 square units

7 0

3 years ago

Read 2 more answers

You will need the same dataset used for problem 3 in homework 1 (the dataset obtained from the yahoo website with the company yo

stepladder [879]

Answer:

a) The probability of sampling at random a fish that is smaller in size than the value you would obtain by subtracting half the standard deviation from the average is 0.3085.

b) The probability of sampling at random a fish that is greater in size than the value you would obtain by adding half the standard deviation from the average is 0.3085.

c) The probability of sampling at random a fish that has a size between the two values is 0.383.

d) The 25th and 75 percentiles of fish size for the population using the normal distribution table is 5.69 and 5.87 respectively.

e) The probability that the average calculated will be less than the value is 0.3707.

Step-by-step explanation:

For the given data set mean $(\mu) = 5.75913$

Standard deviation $(\sigma) = 0.172229$

Variance $(\sigma2) = 0.0296$

Here we get is

$P(x < \mu - \sigma/2) = p(x < 5.673) \\\\ = 0.3085$

$P(x < \mu + \sigma/2) = p(x < 5.845) \\\\= 0.3085$

$P(\mu - \sigma/2 < x < \mu + \sigma/2) = p(5.673 < x < 5.845) \\\\= 0.383$

25th percentile:-

$= 25*[(n+1)/100]th term \\\\= 5.69$

75the percentile:-

$= 75*[(n+1)/100]th term\\\\ = 5.87$

$p(x < \mu - \sigma/3) = p(x < 5.7017) \\\\= 0.3707$

7 0

3 years ago

Carter has 37 coins, all nickels and dimes in his piggy bank. The value of the coins is $3.10. How many dimes does Carter have?

Arisa [49]

The answer is
n = 37 - d
0.05n + 0.10d = 3.10
He has 25 dimes.

n - the number of nickles
d - the number of dimes

n = $0.05
d = $0.10

Carter has 37 coins: n + d = 37
The value of the coins is $3.10: 0.05n + 0.10d = 3.10

n + d = 37
0.05n + 0.10d = 3.10
_____
n = 37 - d
0.05n + 0.10d = 3.10
_____
0.05(37 - d) + 0.10d = 3.10
1.85 - 0.05d + 0.10d = 3.10
1.85 + 0.05d = 3.10
0.05d = 3.10 - 1.85
0.05d = 1.25
d = 1.25 : 0.05
d = 25

3 0

3 years ago

Is 5 a solution of the equation? 13 - d = 8

crimeas [40]

Yes because 13-5=8. not any other single number can be identified in the missing number

3 0

3 years ago

Read 2 more answers

A satellite dish is the shape of a paraboloid. The dish is 38 inches wide, and 10 inches deep. How many inches should the receiv

vitfil [10]

Answer:

9 in approx