Answer:
84
Step-by-step explanation:
Since we are given line OP perpendicular to line DR, then angles PDR and ODR are right angles.
Angles PDA and ADR are complementary.
Angles ODU and UDR are complementary.
Angles ADR and UDR are given as congruent.
We can conclude that angles PDA and ODU are congruent.
By AA Similarity, triangles APD and UMD are similar.
DP/DM = PA/MU
3.75/10 = 4.5/MU
3.75MU = 10 × 4.5
MU = 12 (altitude of triangle DUO)
OD = OM + MD = 4 + 10 = 14 (base of triangle DUO)
area = base × height / 2
area = 14 × 12 / 2
area = 84
Answer:
From the information provided we have:
PD ≅ RD (= 11)
∠CPD ≅ ∠CRD (= 90°)
They both have CD as the hypotenuse.
=> ΔCPD ≅ ΔCRD
=> ∠PCD ≅ ∠RCD
Now we know that:
∠RCP = ∠PCD + ∠RCD
∠RCP = 2 · ∠RCD
∠RCP = 2 · 33° = 66°
So the answer is B
Answer:
Step-by-step explanation:
(simplify)
(Add 3 to both sides)
(simplify)
(Multiply both sides by p)
(Multiply both sides by 2)
(Divide both sides by 7)
