Question

What average force did the block exert on the bullet if it took a time ∆t to stop the bullet?

Answer 1

The average force is $\frac{-mv_0}{\Delta t}$

Explanation:

We can solve this problem by applying the impulse theorem, which states that the impulse exerted on the bullet (product of force and time) is equal to the change in momentum of the bullet:

$F\Delta t = m(v-u)$

where

F is the average force exerted by the block on the bullet

$\Delta t$ is the duration of the collision

m is the mass of the bullet

v is its final velocity

u is its initial velocity

Here we have:

m = m

$u=v_0$

v = 0 (the bullet comes to rest)

And solving for F, we find the average  force:

$F=\frac{m(v-u)}{\Delta t}=\frac{-mv_0}{\Delta t}$

where the negative sign means the direction of the force is opposite to the direction of motion of the bullet.

Learn more about impulse:

brainly.com/question/9484203

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