Answer:
It is doubled.
Explanation:
The EMF( Electromotive force) is usually gotten from an energy source. In this case it is from the magnetic field. However when the other parameters are constant then the main focus is between the EMF and the magnetic field. They have a direct proportion relationship which is why when the magnetic field is doubled the EMF is doubled too.
Answeill give it a go i guess
Explanation:
Year on Gravestone Thickness at bottom Time of weathering AOW
1758 78.5 258 2.4
1766 82.5 79.6 2.4
1758 78.5 258 2.4
1758 78.5 258 2.4
1758 78.5 258 2.4
1758 78.5 258 2.4
1758 78.5 258 2.4
1758 78.5 258 2.4
1758 78.5 258 2.4
1758 78.5 258 2.4
1758 78.5 258 2.4 nvm got lazy
Answer:
W₃ = 3310.49 J
, W3 = 3310.49 J
Explanation:
We can solve this exercise in parts, the first with acceleration, the second with constant speed and the third with deceleration. Therefore it is work we calculate it in these three sections
We start with the part with acceleration, the distance traveled is y = 5.90 m and the final speed is v = 2.30 m / s. Let's calculate the acceleration with kinematics
v2 = v₀² + 2 a₁ y
as they rest part of the rest the ricial speed is zero
v² = 2 a₁ y
a₁ = v² / 2y
a₁ = 2.3² / (2 5.90)
a₁ = 0.448 m / s²
with this acceleration we can calculate the applied force, using Newton's second law
F -W = m a₁
F = m a₁ + m g
F = m (a₁ + g)
F = 69 (0.448 + 9.8)
F = 707.1 N
Work is defined by
W₁ = F.y = F and cos tea
As the force lifts the man, this and the displacement are parallel, therefore the angle is zero
W₁ = 707.1 5.9
W₁ = 4171.89 J W3 = 3310.49 J
Let's calculate for the second part
the speed is constant, therefore they relate it to zero
F - W = 0
F = W
F = m g
F = 60 9.8
F = 588 A
the job is
W² = 588 5.9
W2 = 3469.2 J
finally the third part
in this case the initial speed is 2.3 m / s and the final speed is zero
v² = v₀² + 2 a₂ y
0 = vo2₀² + 2 a₂ y
a₂ = -v₀² / 2 y
a₂ = - 2.3²/2 5.9
a2 = - 0.448 m / s²
we calculate the force
F - W = m a₂
F = m (g + a₂)
F = 60 (9.8 - 0.448)
F = 561.1 N
we calculate the work
W3 = F and
W3 = 561.1 5.9
W3 = 3310.49 J
total work
W_total = W1 + W2 + W3
W_total = 4171.89 +3469.2 + 3310.49
w_total = 10951.58 J
To solve this problem it is necessary to apply the concepts related to electromotive force or induced voltage.
By definition we know that the induced emf in the loop is equal to the negative of the change in the magnetic field, that is,
Where A is the area of the loop, B the magnetic field and t the time.
Replacing with our values we have that
Therefore the thermal energy produced is given by
The thermal energy produced in the loop is 
Answer:
Z
Explanation:
It has the least potential energy in the spring because the spring expanded all the way meaning it is going the fastest
