Answer:
24.71cm
Explanation:
We approach this problem base don Hooke's law which states the elongation produced in an elastic material is proportional to the applied load or force provided that its elastic limit is not exceeded. This is expressed mathematically as follows;
where F is the applied force, k is the force constant and e is the elongation or extension of the material.
In this problem, the applied force F is the weight of the wood which is calculated as follows,
m = 4.11kg
Hence,
Given that k = 163N/m, we make appropriate substitutions into equation (1) to obtain the following;
Since it is required in cm, we perform the conversion as follows, knowing that 100cm = 1m
NB: We do not necessarily need the the density of the wood to perform our calculations since other parameters were given from which we were able to obtain its weight.
Answer:
(a)F= 3.83 * 10^3 N
(b)Altitude=8.20 * 10^5 m
Explanation:
On the launchpad weight = gravitational force between earth and satellite.
W = GMm/R²
where R is the earth radius.
Re-arranging:
WR² / GM = m
m = 4900 * (6.3 * 10^6)² / (6.67 * 10^-11 * 5.97 * 10^24) = 488 kg
The centripetal force (Fc) needed to keep the satellite moving in a circular orbit of radius (r) is:
Fc = mω²r
where ω is the angular velocity in radians/second. The satellite completes 1 revolution, which is 2π radians, in 1.667 hours.
ω = 2π / (1.667 * 60 * 60) = 1.05 * 10^-3 rad/s
When the satellite is in orbit at a distance (r) from the CENTRE of the earth, Fc is provided by the gravitational force between the earth and the satellite:
Fc = GMm/r²
mω²r = GMm / r²
ω²r = GM / r²
r³ = GM/ω² = (6.67 * 10^-11 * 5.97 * 10^24) / (1.05 * 10^-3)²
r³ = 3.612 * 10^20
r = 7.12 * 10^6 m
(a)
F = GMm/r²
F=(6.67 * 10^-11 * 5.97 * 10^24 * 488) / (7.12 * 10^6 )²
F= 3.83 * 10^3 N
(b) Altitude = r - R = (7.12 * 10^6) - (6.3 * 10^6) = 8.20 * 10^5 m
Answer:
The pattern would spread out.
Explanation:
The fringe width is given by the relation
fringe width = λ L / D where λ is wavelength of light used, L is distance of wall from the source of light and D is slit separation.
If we increase λ , fringe width will increase and therefore pattern will spread out .
<em>Choice-C</em> is the right one.
-- The bolt didn't react to the magnet, and just laid there. That tells you that the bolt was made of a non-magnetic material.
-- The bolt didn't float. It went straight to the bottom. That tells you that it's more dense than the fluid around it.
The given question is incomplete. The complete question is as follows.
The block has a weight of 75 lb and rests on the floor for which 
= 0.4. The motor draws in the cable at a constant rate of 6 ft/sft/s. Neglect the mass of the cable and pulleys.
Determine the output of the motor at the instant 
.
Explanation:
We will consider that equilibrium condition in vertical direction is as follows.
N - W = 0
N = W
or, N = 75 lb
Again, equilibrium condition in the vertical direction is as follows.
= 0
= 
= 30 lb
Now, the equilibrium equation in the horizontal direction is as follows.
or, T = 
= 
= 
= 17.32 lb
Now, we will calculate the output power of the motor as follows.
P = Tv
= 
= 
= 0.189 hp
or, = 0.2 hp
Thus, we can conclude that output of the given motor is 0.2 hp.
