The initial temperature of the water was
.
Given,
Weight of glass 36.5g
specific heat for glass is 840 J/kg⋅C∘.
Initial temperature of glass was
.
Weight of water is 145*1=145g (Density*Volume=145ml*1g/ml)
Temperature final was
.
specific heat for water is 4186 J/kgâ‹…Câˆ
(m of glass)(Cp of glass)(Tf_glass-Ti_glass) = (m of water)(Cp of water)(Ti_water - Tf_water)
36.5*840*(40.8-23.6)=145*4186*(Ti_water - 40.8)
Ti_water=
<h3>Specific heat</h3>
In thermodynamics, a material's specific heat capacity, or massic heat capacity as it is sometimes known, is equal to the heat capacity of a sample of the substance divided by the mass of the sample (symbol cp). Informally, it is the quantity of heat needed to raise a substance's temperature by one degree for every unit of mass that is added to it. joule per kelvin per kilogram, or Jkg1K1, is the SI unit for specific heat capacity. For instance, the amount of energy needed to increase the temperature of 1 kilogram of water by 1 K is 4184 joules, making water's specific heat capacity 4184 J kg 1 K 1.
Learn more about specific heat here:
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Answer:
The law which describes the behavior of gases in the Sun is Gay-Lussac's Law
Explanation:
The states that the extremely high pressure of the gases in the Sun produces extremely high temperature;
Therefore, the relationship between the pressure, 'P', of the gas and the temperature, 'T', of the gas is a direct relationship, which can be expressed mathematically as follows;
P ∝ T
The law which best describes the behavior of gases in the Sun is Gay-Lussac's Law, which states that the pressure of a given volume of gas varies directly as the absolute temperature of the gas, as follows;
P = K·T
∴ P/T = K (Constant)

Answer:
The unit of force is Newton.
Explanation:
Given that,
S.I unit of force = kg -m/s²
Time = second
We need to calculate the unit of force
A constant force exerted on the object, an interval of time during
The force is applied and the resulting momentum of the object P.
Using formula of momentum
....(I)
From equation of motion,
v = a t
From newton's second law

Put the value v and a in the equation (I)



Put the unit of the force and time

Here, 

Hence, The unit of force is Newton.
Complete question:
A train has an initial velocity of 44m/s and an acceleration of -4m/s². calculate its velocity after 10s ?
Answer:
the final velocity of the train is 4 m/s.
Explanation:
Given;
initial velocity of the train, u = 44 m/s
acceleration of the train, a = -4m/s² (the negative sign shows that the train is decelerating)
time of motion, t = 10 s
let the final velocity of the train = v
The final velocity of the train is calculated using the following kinematic equation;
v = u + at
v = 44 + (-4 x 10)
v = 44 - 40
v = 4 m/s
Therefore, the final velocity of the train is 4 m/s.
Answer:
The first answer is W and Z, since they appear to be a period apart. Dont know the second question. I did what I could, hope someone can answer the second.