Try this solution:
if given m=0.15 kg; t₁=20 °C; t₂=100 °C; c=4190 J/(kg*C); q=226*10⁴ J/kg., then
Q=Q₁+Q₂,
where Q₁=cm(t₂-t₁) and Q₂=q*m.
Finally,
Q=cm(t₂-t₁)+qm;
Q=4190*0.15*80+2240000*0.15=386280 J=<u>386.28 kJ</u>.
Answer:
a. Point A
b. 20 V
c. 100 J
Explanation:
a. Point A is at a higher potential because there is a positive sign in front of its magnitude. Since it is a positive integral value, and has a higher magnitude than point B which is at -4, point A is thus at a higher potential than point B.
b. The potential difference between the two points ΔV = A - B
= +16 V - (-4 V)
= +16 V + 4 V
= + 20 V
c. The work done, W in moving a charge Q across a potential difference ΔV is W = QΔV
So, since Q = 5 C and ΔV = + 20 V
W = QΔV
= 5 C × (+ 20 V)
= 100 J
Answer:
w = 706.32 [N]
Explanation:
The force due to gravitational acceleration can be calculated by means of the product of mass by gravitational acceleration.
w = m*g
where:
w = weight [N] (units of Newtons)
m = mass = 72 [kg]
g = gravity acceleration = 9.81 [m/s²]
Then we have:
![w = 72*9.81\\w = 706.32 [N]](https://tex.z-dn.net/?f=w%20%3D%2072%2A9.81%5C%5Cw%20%3D%20706.32%20%5BN%5D)
<span>The answer is 15 centimeters. The waves with the
smallest wavelengths (also highest
frequency) have the least capacity to diffract around objects hence have a
shadowing effect, behind the object, especially if the wavelength is small
compared to the object. This is also the reason why high-frequency electromagnetic waves do not have a good reach in mountainous
regions. </span>
The escape velocity on Venus is 9761 m/s
Explanation:
The escape velocity from a planet is the speed that an object on the surface of that planet must have in order to completely escape the gravitational field of the planet.
Mathematically, it is calculated as

where
G is the gravitational constant
M is the mass of the planet
R is the radius of the planet
For Venus, we have:
is the mass
is the radius
Substituting, we find the escape velocity on Venus:

Learn more about velocity:
brainly.com/question/5248528
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