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irinina [24]
3 years ago
9

A cylinder with a movable piston contains 2.00 g of helium, He, at room temperature. More helium was added to the cylinder and t

he volume was adjusted so that the gas pressure remained the same. How many grams of helium were added to the cylinder if the volume was changed from 2.00 L to 4.10 L ? (The temperature was held constant.)
Physics
1 answer:
Katen [24]3 years ago
5 0

Answer:

0.358g

Explanation:

Density of Helium = 0.179g/L

ρ=m/v

m=ρv

when the volume was 2L

m1= 0.179*2

m1=0.358g

when the volume increased to 4L

m2= 0.179*4

m2=0.716g

gram of helium added = 0.716g-0.358g

=0.358g

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for a moving object distance covered by it is always greater than or equal to the displacement of the object in a given time. ex
AleksandrR [38]
<h3><u>Answer</u></h3>

  • Distance is equal to the Total Distance covered by a body, from the initial till the final point.

  • Displacement is equal to the shortest distance between two points.

  • So we known that Distance can only be equal to or greater than the displacement and can never be shorter than the displacement.

  • This is just common sense how can anything be shorter than the shortest path itself. But it can be equal to the shortest path
<h3>━━━━━━━━━━━━━━</h3>

<h3><u>Know </u><u>More</u></h3>

☯ Distance is a scalar quantity and has only magnitude but no direction.

☯ Displacement is a vector quantity and has both magnitude and direction.

☯ Distance can only have +ve values whereas displacement can be +ve, -ve or even be zero.

6 0
3 years ago
In a football game, the running back takes a handoff and begins running toward midfield at 3.21 yards/s . As he moves through hi
Inessa [10]

Given Information:

Initial speed = u = 3.21 yards/s

Acceleration = α  = 1.71 yards/s²

Final speed = v = 7.54 yards/s

Required Information:

Distance = s = ?

Answer:

Distance = s = 13.61

Explanation:

We are given the speeds and acceleration of the runner and we want to find out how much distance he covered before being tackled.

We know from the equations of motion,

v² = u² + 2αs

Where u is the initial speed of the runner, v is the final speed of the runner, α is the acceleration of the runner and s is the distance traveled by the runner.

Re-arranging the above equation for distance yields,

2αs = v² - u²

s = (v² - u²)/2α

s = (7.54² - 3.21²)/2×1.71

s = 46.55/3.42

s = 13.61 yards

Therefore, the runner traveled a distance of 13.61 yards before being tackled.

8 0
3 years ago
A baseball has 5.8kg*m/s momentum before being hit by the bat. After being hit it has 6.79 kg*m/s in the opposite direction. Wha
fomenos

Answer:

0.99kgm/s

Explanation:

Given parameters:

Initial momentum  = 5.8kgm/s

Final momentum  = 6.79kgm/s

Unknown:

Magnitude of the impulse applied to the baseball  = ?

Solution:

To solve this problem;

 The impulse applied to the baseball can be found by using the expression below:

 Impulse  = Final momentum   -   Initial momentum

Impulse  = 6.79kgm/s - 5.8kgm/s  = 0.99kgm/s

8 0
3 years ago
Web Spiders and Oscillations All spiders have special organs that make them exquisitely sensitive to vibrations. Web spiders det
Leokris [45]

Answer:

0.037 N/m

Explanation:

The web acts as a spring, so it obeys Hook's law:

F=kx (1)

where

F is the force exerted on the web

k is the spring constant

x is the stretching/compression of the web

In this problem, we have:

- The mass of the fly is m=15 mg=15\cdot 10^{-6} kg

- The force exerted on the web is the weight of the fly, so:

F=mg=(15\cdot 10^{-6}kg)(9.81 m/s^2)=1.47\cdot 10^{-4}N

- The stretching of the web is

x=4.0 mm=0.004 m

So if we solve eq.(1) for k, we find the spring constant:

k=\frac{F}{x}=\frac{1.47\cdot 10^{-4} N}{0.004 m}=0.037 N/m

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3 years ago
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Mrac [35]

Answer:

C

Explanation:

Exercise also increases your levels of HDL cholesterol, the "good" cholesterol that lowers heart disease risk by flushing the artery-clogging LDL or "bad" cholesterol out of your system.

5 0
3 years ago
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