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Galina-37 [17]
2 years ago
8

Write the net cell equation for this electrochemical cell. Phases are optional. Do not include the concentrations. Co ( s ) ∣ ∣

Co 2 + ( aq , 0.0155 M ) ∥ ∥ Ag + ( aq , 1.50 M ) ∣ ∣ Ag ( s )
Chemistry
1 answer:
Tatiana [17]2 years ago
5 0

Answer: The overall equation will be Co(s)+2Ag^+(aq)\rightarrow Co^{2+}(aq)+Ag(s)

Explanation:

The representation is given by writing the anode on left hand side followed by its ion with its molar concentration. It is followed by a salt bridge. Then the cathodic ion with its molar concentration is written and then the cathode.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

Anode : Co(s)\rightarrow Co^{2+}(aq)+2e^{-}

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

Cathode : Ag^+(aq)+e^{-1}\rightarrow Ag(s)  \times 2

The number of electrons lost must be equal to the number of electrons gained , thus overall equation will be :

Co(s)+2Ag^+(aq)\rightarrow Co^{2+}(aq)+Ag(s)

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2 years ago
Which is smaller 25 mm or 25cm
umka21 [38]

Answer:

25 mm is smaller.

5 0
3 years ago
A substance X contains 10 gram of calcium carbonate calculate the number of mole of calcium carbonate present in X ​
Tasya [4]

\LARGE{ \boxed{  \rm{ \red{Required \: answer}}}}

☃️ Chemical formulae ➝ \sf{CaCO_3}

<h3><u>How to find?</u></h3>

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

\boxed{ \sf{No. \: of \: moles =  \frac{given \: weight}{molecular \: weight} }}

<h3><u>Solution:</u></h3>

Atomic weight of elements:

Ca = 40

C = 12

O = 16

❍ Molecular weight of \sf{CaCO_3}

= 40 + 12 + 3 × 16

= 52 + 48

= 100 g/mol

❍ Given weight: 10 g

Then, no. of moles,

⇛ No. of moles = 10 g / 100 g mol‐¹

⇛ No. of moles = 0.1 moles

☄ No. of moles of Calcium carbonate in that substance = <u>0.1 moles</u>

<u>━━━━━━━━━━━━━━━━━━━━</u>

3 0
3 years ago
Read 2 more answers
The unsaturated hydrocarbon butadiene (C4H6) dimerizes to 4-vinylcyclohexene (C8H12). When data collected in studies of the kine
UkoKoshka [18]

Answer:

The dimerization of butadiene to 4-vinylcyclohexene folows second order kinetics and its rate law will be given by :

R=k[C_4H_6]^2

Explanation:

2C_4H_6\rightarrow C_8H_{12}

The rate of the reaction ;

R=k[C_4H_6]^x

As given in the question , that graph of time verses \frac{1}{[C_4H_6]} was linear but plots of [C_4H_6] or \ln[C_4H_6]  was curved.

Generally:

Graph of time verses [concentration] for zero order reaction is linear with negative slope.

Graph of time verses \ln [concentration] for secon order reaction is linear with negative slope.

Graph of time verses \frac{1}{[concentration]} for secon order reaction is linear with positive slope.

So, the dimerization of butadiene to 4-vinylcyclohexene folows second order kinetics and its rate law will be given by :

R=k[C_4H_6]^2

3 0
2 years ago
A saturated solution of pbcl2 is found to contain 2.88 x 10-2 m chloride ions. what is the correct value of the solubility produ
bazaltina [42]

The solubility equilibrium of PbCl_{2}:

PbCl_{2}(aq)  Pb^{2+}(aq) + 2 Cl^{-}(aq)

K_{sp}=[Pb^{2+}][Cl^{-}]^{2}

[Cl^{-}] = 2.88 * 10^{-2} M

[Pb^{2+}]=\frac{[Cl^{-}]}{2} = \frac{2.88 * 10^{-2}}{2}=1.44 *10^{-2}

K_{sp}=[Pb^{2+}][Cl^{-}]^{2}

= (1.44 * 10^{-2})(2.88*10^{-2})^{2}

= 1.19 * 10^{-5}

So, the corrected solubility product will be 1.19 * 10^{-5}

4 0
3 years ago
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