Answer:
AT THE END OF 80% DISSOLUTION, THE PRESSURE OF NO2 HAS CHANGED FROM 99kPa TO 139.97kPa
Explanation:
P1 = 99 kPa
P2 = unknown
From the reaction,
2 mole of NO2 will produce 2 mole of NO
We can also say that 1 mole of NO2 will produce 1 mole of NO
At 56.6 % of NO2, 0.566 mole of NO2 will be consumed
At STP, 1 mole of a substance will occupy 22.4 dm3 volume
0.566 mole will occupy ( 22.4 * 0.566 / 1) dm3 volume
= 39.58 dm3 volume
V1 = 39.56 dm3
At the new percent of 80%, 0.80 mole of NO2 will be consumed
Since, 1 mole = 22.4 dm3
0.80 mole = (22.4 / 0.80) dm3
= 28 dm3
V2 = 28 dm3
Using the equation of Boyle's law which shows the relationship between pressure and volume of a given mass of gas at constant temperature, we have:
P1 V1 = P2 V2
Re-arranging to make P2 the subject of formula:
P2 = P1V1 / V2
P2 = 99 kPa * 39.56 / 28
P2 = 3916.44 kPa / 28
P2 = 139.87 kPa
So at 80 % dissociation of NO2, the pressure has changed from 99 kPa to 139.97 kPa.
Answer:
a) The carbon-carbon bonds rapidly alternate between single and double bonds.
Explanation:
In benzene we have that the molecule is planar with an sp² hybridization that allow for three π bonds and the carbons atoms are also bonded together via sigma a sp² hibridization as well as one hydrogen atom. The alternation of or conjugation of the π bond allow the delocalization of these electron along the whole ring.
Therefore, a) is false the carbon-carbon bonds rapidly alternate between single and double bond. The electrons in the π bonds are completely delocalized through the six atoms in the ring.
b) is true since we have a sp² hybridization.
c) and d) are true for the reasons given previously.
Answer:
The atoms in a gas move at high speeds