Answer:
solubility of X in water at 17.0
is 0.11 g/mL.
Explanation:
Yes, the solubility of X in water at 17.0
can be calculated using the information given.
Let's assume solubility of X in water at 17.0
is y g/mL
The geochemist ultimately got 3.96 g of crystals of X after evaporating the diluted solution made by diluting the 36.0 mL of stock solution.
So, solubility of X in 1 mL of water = y g
Hence, solubility of X in 36.0 mL of water = 36y g
So, 36y = 3.96
or, y =
= 0.11
Hence solubility of X in water at 17.0
is 0.11 g/mL.
They are called carcinogens
Answer: covalent bond
Explanation: Tetracarbon Hexahyride is built using covalent bonds
Hope this helps please mark brainlist it would be greatly appreiciated :)
We can solve this problem using Raoults law. The formula
for Raoults law is:
P_a = X_a * P
where,
P_a = the partial pressure of substance A
X_a = the mole fraction of substance A
P = total pressure
Therefore calculating for P:
P = P_a / X_a
P = 0.580 atm / 0.35
<span>P = 1.657 atm</span>